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2 years ago

11

A certain television is advertised as a 21-inch TV (the diagonal length). If the height of the TV is 13 inches, how wide is the

TV? Round to the nearest tenth of an inch.

1 answer:

kolbaska11 [484]2 years ago

3 0

Answer:

16.5 inches

Step-by-step explanation:

Use the Pythagorean Theorem

a² + b² = c²

a² + 13² = 21²

a² + 169 = 441

Subtract 169 from both sides

a² = 272

Take the square root of both sides

a = 16.4924225025

Rounded

a = 16.5 inches

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Which number line shows the graph of -2.75 -3<br> -2<br> -1<br> 0<br> 1<br> 2<br> 3<br> 0<br> 1<br> 2.<br> 3<br> -3 -2<br> -1<br

nikklg [1K]

Answer:

I believe the answer is A, the first option.

Step-by-step explanation:

I haven't done this in a whlie but to my memory, I think its A.

4 0

3 years ago

Read 2 more answers

A soup can in the shape of a right circular cylinder is to be made from two materials. The material for the side of the can cost

Advocard [28]

Answer:

Radius = 1.12 inches and Height = 4.06 inches

Step-by-step explanation:

A soup can is in the shape of a right circular cylinder.

Let the radius of the can is 'r' and height of the can is 'h'.

It has been given that the can is made up of two materials.

Material used for side of the can costs $0.015 and material used for the lids costs $0.027.

Surface area of the can is represented by

S = 2πr² + 2πrh ( surface area of the lids + surface are of the curved surface)

Now the function that represents the cost to construct the can will be

C = 2πr²(0.027) + 2πrh(0.015)

C = 0.054πr² + 0.03πrh ---------(1)

Volume of the can = Volume of a cylinder = πr²h

16 = πr²h

$h=\frac{16}{\pi r^{2}}$ -------(2)

Now we place the value of h in the equation (1) from equation (2)

$C=0.054\pi r^{2}+0.03\pi r(\frac{16}{\pi r^{2}})$

$C=0.054\pi r^{2}+0.03(\frac{16}{r})$

$C=0.054\pi r^{2}+(\frac{0.48}{r})$

Now we will take the derivative of the cost C with respect to r to get the value of r to get the value to construct the can.

$C'=0.108\pi r-(\frac{0.48}{r^{2} })$

Now for C' = 0

$0.108\pi r-(\frac{0.48}{r^{2} })=0$

$0.108\pi r=(\frac{0.48}{r^{2} })$

$r^{3}=\frac{0.48}{0.108\pi }$

r³ = 1.415

r = 1.12 inch

and h = $\frac{16}{\pi (1.12)^{2}}$

h = 4.06 inches

Let's check the whether the cost is minimum or maximum.

We take the second derivative of the function.

$C"=0.108+\frac{0.48}{r^{3}}$ which is positive which represents that for r = 1.12 inch cost to construct the can will be minimum.

Therefore, to minimize the cost of the can dimensions of the can should be

Radius = 1.12 inches and Height = 4.06 inches

5 0

3 years ago

What is the quadratic. Formula?

balu736 [363]

Answer:

$x = \frac{ - b ± \sqrt{ {b }^{2} - 4ac } }{2a}$

Step-by-step explanation:

For example, we'll use this quadratic equation.

${x}^{2} + 5x + 6$

To understand how to plug it into the formula we need to know what each term represents.

$a {x}^{2} + bx + c$

So the equation above would be put into the formula like this.

$x = \frac{ - 5± \sqrt{ {5}^{2} - 4(1)(6) } }{2(1)}$

Then we would solve

$\frac{ - 5± \sqrt{25 - 24} }{2} \\ \\ = \frac{ -5±1}{2}$

Now, the equation will branch off into one that solves when addition and one when subtraction.

$\frac{ - 5 + 1}{2} = \frac{ - 4}{2} = - 2 \\ \\ \frac{ - 5 - 1}{2} = \frac{ - 6}{2} = - 3$

So x={-3, -2} (-3 and -2)

6 0

3 years ago

What is the missing length 11 + = ×16 = ÷2 =209

zzz [600]

11 plus what number equals 16 in order to complete your problem.

3 0

3 years ago

Joe's annual income has been increasing each year by the same dollar amount. The first year his income was $17 comma 90017,900

Vedmedyk [2.9K]

Answer:

In 17th year, his income was $30,700.

Step-by-step explanation:

It is given that the income has been increasing each year by the same dollar amount. It means it is linear function.

Income in first year = $17,900

Income in 4th year = $20,300

Let y be the income at x year.

It means the line passes through the point (1,17900) and (4,20300).

If a line passes through two points $(x_1,y_1)$ and $(x_2,y_2)$ , then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

The equation of line is

$y-17900=\frac{20300-17900}{4-1}(x-1)$

$y-17900=\frac{2400}{3}(x-1)$

$y-17900=800(x-1)$

$y-17900=800x-800$

Add 17900 on both sides.

$y=800x-800+17900$

$y=800x+17100$

The income equation is y=800x+17100.

Substitute y=30,700 in the above equation.

$30700=800x+17100$

Subtract 17100 from both sides.

$30700-17100=800x$

$13600=800x$

Divide both sides by 800.

$\frac{13600}{800}=x$

$17=x$

Therefore, in 17th year his income was $30,700.

5 0

3 years ago