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Levart [38]
2 years ago
11

A certain television is advertised as a 21-inch TV (the diagonal length). If the height of the TV is 13 inches, how wide is the

TV? Round to the nearest tenth of an inch.
Mathematics
1 answer:
kolbaska11 [484]2 years ago
3 0

Answer:

16.5 inches

Step-by-step explanation:

Use the Pythagorean Theorem

a² + b² = c²

a² + 13² = 21²

a² + 169 = 441

Subtract 169 from both sides

a² = 272

Take the square root of both sides

a = 16.4924225025

Rounded

a = 16.5 inches

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Answer:

10010

Step-by-step explanation:

1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0

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1(2)^3+0(2)^2+1(2)^1+1(2)^0

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-----------------------------------------------------

Combine like terms:

1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0

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We aren't allowed to have a coefficient bigger than 1.

I'm going to replace 2^0 with 1 and 2 with (2)^1:

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I want a 2^0 number:

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Combine like terms:

1(2)^3+2(2)^2+1(2)^1+0(2)^0

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Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

      1     0     1      1

+            1      1      1

------------------------------

     (1)    (1)    (1)

      1     0     1      1

+            1      1      1

------------------------------

     1 0    0     1       0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

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