The equation in slope-intercept form of the line that passes through the point (-1, 2) and is perpendicular to the line equation, is:
<em><u>Recall</u></em>:
Equation of a line in slope-intercept form is: , where, slope = m, and y-intercept = c.
Point-slope form is:
The slope value of a line will be the negative reciprocal of the slope of the line it is perpendicular to. i.e. if the slope of a line is a, the slope of the line that it is perpendicular to will be -a.
<em><u>Given:</u></em>
- The line passes through point (-1, 2)
- Equation of line it is perpendicular to is:
To write the equation of the line that passes through (-1, 2), we need to find the slope value.
- First, rewrite and find its slope.
- The slope (m) of is therefore 1.
- Thus, the slope (m) of the line that passes through (-1, 2) will be the negative reciprocal of 1 = -1.
- Write the equation of the line by substituting (a, b) = (-1, 2) and m = -1 into :
- Rewrite this in the form of
Therefore, the equation in slope-intercept form of the line that passes through the point (-1, 2) and is perpendicular to the line equation, is
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yeah, they probably are because 360-130-50=180 and both of the angles look like they could be 90 degrees
Answer:
4:18 pm
Step-by-step explanation:
An airport offers 2 shuttles that run on different schedules.If both shuttles leave the airport at 4:00 p.m.,at what time will they next leave theairport together.
Shuttle A leaves every 6 minutes
Shuttle B leaves every 9 minutes
Solution
To solve for when next both shuttles will leave the airport together, find the least common multiples of 6 minutes and 9 minutes
Shuttle A (every 6 minutes) = 6, 12, 18, 24
Shuttle B (every 9 minutes) = 9, 18, 27, 36
The least common multiples of 6 minutes and 9 minutes is 18 minutes
4:00 pm + 18 minutes
= 4:18 pm
The next time both shuttles will leave theairport together is 4:18 pm of the same day
Answer:
Step-by-step explanation:
Subset of A = { {} , {a} , {b}, {a.b} }
Time = distance/speed, so
3.54x10^7 / 3x10^8 = 1.18x10^-1
or, 0.118 seconds