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4 years ago

What is m What is m What is m

Mathematics

1 answer:

Nadya [2.5K]4 years ago

8 0

Answer:

honestly im not sure but i am doing that same work at the moment and i just ingore the m. it shouldnt change what you get as your answer.

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. (02.05 MC) Side AB = 5, side BC = 6, side DE = 5, and side EF = 6. What additional information would you need to prove that ΔA

vaieri [72.5K]

Answer:

Side AC is congruent to side DF

Step-by-step explanation:

We are given that

Side AB=5 cm

BC=6 cm

Side DE=5 cm

Side EF= 6cm

We have to find an additional information would need to prove that $\triangle ABC\cong \triangle DEF$ by SSS.

When two triangles are congruent by SSS it means three sides of one triangle are congruent to corresponding sides of other triangle.

We have in triangle ABC and triangle DEF

$AB\cong DE=5 cm$

$BC\cong EF=6 cm$

$AC\cong DF$

Then , $\triangle ABC\cong \triangle$ DEF

Reason: SSS postulates

Answer: Side AC is congruent to side DF

8 0

3 years ago

Porfabor necesito ayuda en la esta pregunta. ¿Encuentra cuatro pares ordenados de la siguiente función? f(x) = X3 – 2X2 – 2

zlopas [31]

Answer:

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de $f(x) = x^{3}-2\cdot x^{2}-2$ .

Step-by-step explanation:

Un par ordenado es un elemento de la forma $(x,f(x))$ , donde $x$ es un elemento del dominio de la función, mientras $f(x)$ es la imagen de la función evaluada en $x$ . Entonces, un par ordenado que está contenido en la citada función debe satisfacer la siguiente condición:

La imagen de la función existe para un elemento dado del dominio. Esto es:

$x \rightarrow f(x)$

Dado que $f(x)$ es una función polinómica, existe una imagen para todo elemento $x$ . Ahora, se eligen elementos arbitrarios del dominio para determinar sus imágenes respectivas:

x = 0

$f(0) = 0^{3}-2\cdot (0)^{2}-2$

$f(0) = -2$

(0, -2) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 1

$f(1) = 1^{3}-2\cdot (1)^{2}-2$

$f(1) = -3$

(1, -3) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 2

$f(2) = 2^{3}-2\cdot (2)^{2}-2$

$f(2) = -2$

(2, -2) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 3

$f(3) = 3^{3}-2\cdot (3)^{2}-2$

$f(3) = 7$

(3, 7) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de $f(x) = x^{3}-2\cdot x^{2}-2$ .

6 0

3 years ago

Find the area of a circular pond having radius Ans: 616 m 14 m.

krek1111 [17]

Step-by-step explanation:

Area of circular pond=22/7×14×14

=22/7×196

=616m

3 0

3 years ago

The area of a room is 600 square feet. The length is (x + 5) feet and the width is (x + 4) feet. Find the dimensions of the room

tangare [24]

I'm going to assume that the room is a rectangle.

The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle.

You're given that the length, l = (x+5)ft and the width, w = (x+4)ft. You're also told that the area, A = 600 sq. ft. Plug these values into the equation for the area of a rectangle and FOIL to multiply the two factors:
$A = lw\\
600 = (x+5)(x+4)\\
600 = x^{2} + 9x + 20
$

Now subtract 600 from both sides to get a quadratic equation that's equal to zero. That way you can factor the quadratic to find the roots/solutions of your equation. One of the solutions is the value of x that you would use to find the dimensions of the room:
$600 = x^{2} + 9x + 20\\
x^{2} + 9x - 580 = 0\\
(x + 29)(x - 20) = 0\\
x + 29 = 0, \:\: x - 20 = 0\\
x = -29, x = 20$

Now you know that x could be -29 or 20. For dimensions, the value of x must give you a positive value for length and width. That means x can only be 20. Plugging x=20 into your equations for the length and width, you get:
Length = x + 5 = 20 + 5 = 25 ft.
Width = x + 4 = 20 + 4 = 24 ft.

The dimensions of your room are 25ft (length) by 24ft (width).

8 0

4 years ago

Read 2 more answers

SAY SOMETHING OD FOR F R E E POINTS IT DOES NOT MATER WHAT IT IS OK.

marissa [1.9K]

Answer:

LESS GO

Step-by-step explanation:

U DA BEST

6 0

3 years ago

Read 2 more answers