Answer:
To the nearest hundred dollars, the car will be worth $17,900 by 2005
Step-by-step explanation:
Firstly, we need to write the depreciation equation
We have this as:
V = I(1 - r)^t
V is the present value which is what we want to calculate
I is the initial value, the amount the cad was bought which is $22,000
r is the rate of change which is 5% = 5/100 = 0.05
t is the time difference which is 2005-2001 = 4
Substituting all these into the depreciation equation, we have it that
V = 22,000(1 -0.05)^4
V = $17,919.1375
To the nearest hundred dollars, that would be;
$17,900
Answer: I don’t think I understand can you set this up differently so I can answer this please
Step-by-step explanation:
Answer:
n=22 or 252=11(22)+10
Step-by-step explanation: 252=11n+10. Start by attempting to isolate the varyable by subracting 10 from both sides--> 242=11n, divide by 11--> 22=n
PROOF 252=11*22+10=242+10=252
First off you need to multiply 6 by 3 for how many miles she went and then divide the leftover total by two (For the last two hours) to realize she needs to run 4.1 mph.
Hope this helped :)
Answer:
third option (-3,3,5,9)
Step-by-step explanation:
domain is the starting point of the set (x coordinate )
