Answer:
see below
Step-by-step explanation:
The formula for the sum of an infinite geometric series with first term a1 and common ratio r (where |r| < 1) is ...
sum = a1/(1 -r)
Applying this to the given series, we get ...
a. sum = 5/(1 -3/4) = 5/(1/4) = 20
b. sum = d/(1 -1/t) = d/((t-1)/t) = dt/(t-1)
_____
The derivation of the above formula is in most texts on sequences and series. In general, you write an expression for the difference of the sum (S) and the product r·S. You find all terms of the series cancel except the first and last, and the last goes to zero in the limit, because r^∞ → 0 for |r| < 1. Hence you get ...
S -rS = a1
S = a1/(1 -r)
5/10 in 3 equivalent forms is: 1/2 2/4 4/8
Answer:
Step-by-step explanation:
just means 
.
So
Answer:
729
Step-by-step explanation:
I have not done this in some time so the terms may be a bit unconventional, but they work. The key to this is multiplying by -3.
1*(-3) = -3
-3*(-3) = 9
And so on.
1, -3, 9, -27, 81, -243, 729
Answer:
10
Step-by-step explanation:
