Answer:
A. 264
Step-by-step explanation:
First, we have to find the value of x. Then we can use that to find the required arc measure.
∠M = (1/2)(arc KN - arc LN)
60 = (1/2)((18x -6) -(5x +17)) = (1/2)(13x -23) . . . . substitute and simplify
120 = 13x -23 . . . . . . . multiply by 2
143 = 13x . . . . . . . . . . add 23
11 = x . . . . . . . . . . . . . . divide by 13
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arc KNL = (arc KN) + (arc NL) = (18x -6) +(5x +17) = 23x +11
= 23·11 +11
arc KNL = 264 . . . . degrees
(a) It is leaking 18 liters per minute.
Explanation : From 15 minutes to 20 minutes, your starting point at 15 is 590 liters and at 20 you have exactly 500. Next you have 25 which is now at 410. So it's leaking 90 liters every five minutes, so of course dividing the two (90 ÷ 5) you get 18.
(a)² it increases for about the same time that it would decrease of course.
(b) The vat started at 860 liters before they started draining it.
Explanation : Well, all it takes is just working backwards, add 90 liters to the liters at 15 minutes and deduct five minutes from 15. Do this process until you arrive at 0. It's simple
9514 1404 393
Answer:
- late only: 15
- extra-late only: 24
- one type: 43
- total trucks: 105
Step-by-step explanation:
It works well when making a Venn diagram to start in the middle (6 carried all three), then work out.
For example, if 10 carried early and extra-late, then only 10-6 = 4 of those trucks carried just early and extra-late.
Similarly, if 30 carried early and late, and 4 more carried only early and extra-late, then 38-30-4 = 4 carried only early. In the attached, the "only" numbers for a single type are circled, to differentiate them from the "total" numbers for that type.
__
a) 15 trucks carried only late
b) 24 trucks carried only extra late
c) 4+15+24 = 43 trucks carried only one type
d) 38+67+56 -30-28-10 +6 +6 = 105 trucks in all went out
Answer:
The Z is has no lines of symmetry. The W and Y have one line of symmetry. The X has two lines of symmetry.
It would take 24 days for the patch to cover half of the lake
