What is 2 1/2 ft × 3 1/2 ft
2 answers:
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we have that
using a graph tool
see the attached figure
statements
case a) The domain is {x|x ≤ –2}-------> Is False
the domain is all real numbers---------> the interval (-∞,∞)
case b) The range is {y|y ≤ 6}.------> Is True
The range is the interval (-∞,6]
case c) The function is increasing over the interval (–∞ , –2).-----> Is True
See the attached figure
case d)The function is decreasing over the interval (−4, ∞).-----> Is False
In the interval (-4,-2) the function is increasing and in the interval (-2,∞) the function is decreasing (See the attached figure)
case e)The function has a positive y-intercept.------> Is True
The value of y-intercept is
Hi! You don't actually need to graph this nor find the intersection in order to know the answer. Through the process of elimination we can rule out incorrect answers.
Firstly, we express both equations with y on the left hand side since all choices are in that form:
Knowing these, we can immediately rule out options a, c, and d since they have the wrong equations. This will leave us with option b.
You can verify if the point of intersection provided in option b is true by plugging in the values of x and y to both equations (you will find that it is indeed true).
ANSWER: b. <span>picture of coordinate plane with line y equals negative 2x minus 1 and line y equals negative 3 halves x minus 3. They intersect at 4, negative 9.</span>
Firstly, we express both equations with y on the left hand side since all choices are in that form:
Knowing these, we can immediately rule out options a, c, and d since they have the wrong equations. This will leave us with option b.
You can verify if the point of intersection provided in option b is true by plugging in the values of x and y to both equations (you will find that it is indeed true).
ANSWER: b. <span>picture of coordinate plane with line y equals negative 2x minus 1 and line y equals negative 3 halves x minus 3. They intersect at 4, negative 9.</span>
Answer:
Step-by-step explanation:
The identities you need here are:
and
You also need to know that
x = rcosθ and
y = rsinθ
to get this done.
We have
r = 6 sin θ
Let's first multiply both sides by r (you'll always begin these this way; you'll see why in a second):
r² = 6r sin θ
Now let's replace r² with what it's equal to:
x² + y² = 6r sin θ
Now let's replace r sin θ with what it's equal to:
x² + y² = 6y
That looks like the beginnings of a circle. Let's get everything on one side because I have a feeling we will be completing the square on this:
Complete the square on the y-terms by taking half its linear term, squaring it and adding it to both sides.
The y linear term is 6. Half of 6 is 3, and 3 squared is 9, so we add 9 in on both sides:
In the process of completing the square, we created within that set of parenthesis a perfect square binomial:
And there's your circle! Third choice down is the one you want.
Fun, huh?