Let n be the sum of all 6 numbers:
In the 1st case n/6 = 41 ==> n =246
in the 2nd case n'/5 = 46===> n' =230, the unknown number is n-n' =246-230
= 16
Answer:
Following are the solution to the given question:
Step-by-step explanation:
Please find the complete question in the attached file.
The testing states value is:
therefor the 
Through out the above equation its values Doesn't rejects the H_0 value, and its sample value doesn't support the claim that although the configuration of its dependent variable has been infringed.
Answer:
x^7 + x^6 - 3x^4 + 4x^3 + 6x - 3.
Step-by-step explanation:
(x3 + 2x - 1) (x4 - x3 + 3)
= x^7 - x^6 + 3x^3 + 2x^6 - 2x^4 + 6x - x^4 + x^3 - 3
= x^7 + x^6 - 3x^4 + 4x^3 + 6x - 3.
A₆ =12
a₇ = ?? = x
a₈ 27
In this case x is the geometric mean & as per the formula
geometric mean of 2 numbers =√(a₆ * a₈) = √(12*27)
& x=18.
Proof:
Find the common ratio between a₇ & a₆ ==> = ( x) / 12
now find the common ration between a₈ & a₇ ===> =27 / (x)
x/12 = 27/x ===> x² = 12*27 ==> x² = 324 & x =√324 = 18
Well 3 3/8 as a decimal is 3.375 and 1 5/6 as a decimal is 1.8333333333 and if you add those its <span>5.208333333</span>.
