Can someone help me with these problems please!
2 answers:
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Using the z-table, the probability that a student taking this test will finish in 100 minutes or less is 0.0824 or 8.24%.
For a normally distributed set of data, given the mean and standard deviation, the probability can be determined by solving the z-score and using the z-table.
First, solve for the z-score using the formula below.
z-score = (x – μ) / σ
where x = individual data value = 100
μ = mean = 125
σ = standard deviation = 18
z-score = (100 – 125) / 18
z-score = (-25) / 18
z-score = -1.39
Find the probability that corresponds to the z-score in the z-table. (see attached images)
-1.39 - (-1.3) : -1.4 - (-1.3) = x - 0.0968 : 0.0808 - 0.0968
-0.09 : -0.1 = x - 0.0968 : -0.016
x - 0.0968 = -0.09(-0.016)/-0.1
x = -0.0144 + 0.0968
x = 0.0824
x = 0.0824
Hence, the probability that a student taking this test will finish in 100 minutes or less is 0.0824 or 8.24%.
Learn more about probability here: brainly.com/question/26822684
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Answer:
The price of 1 adult ticket is $ 11 and price of 1 child ticket is $13
Step-by-step explanation:
Let x be the cost of 1 adult ticket
Let y be the cost of 1 child ticket
Cost of 8 adult tickets = 8x
Cost of 9 child tickets = 9y
We are given that A local kids play sold 8 adult tickets and 9 child tickets for a total of $205
So, 8x+9y=205 ----- 1
Cost of 4 adult tickets = 4x
Cost of 3 child tickets = 3y
We are given that 4 adult tickets and 3 child tickets for a total of $83.
4x+3y=83 ----2
Plot 1 and 2 on graph
8x+9y=205 -- Red line
4x+3y=83 -- Blue line
Intersection point provides the solution
So, Intersection point =(11,13)
So, The price of 1 adult ticket is $ 11 and price of 1 child ticket is $13
