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NikAS [45]
2 years ago
11

Tell whether the sequence is arithmetic. If it is, what is the common difference?

Mathematics
1 answer:
denis23 [38]2 years ago
6 0
Idek sorry have a nice day
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Please solve the table correctly.
Hitman42 [59]

Answer:

See below.

Step-by-step explanation:

No. Triangles       Perimeter

 1                                  14

2                                  18

3                                  22

We see from the table, after the first  perimeter  (= 14),  with  each increase of 1 in the number of triangles,  the perimeter increases by 4.

As an equation it is  P = 14 + 4(n - 1)  where P = perimeter and n = number of triangles.

4 0
3 years ago
What's the correct answer to this..? Please help
mestny [16]

Answer:

D. {x:-8≤x<-5}

Step-by-step explanation:

x≥-8

x={-8,-7,-6,-5,-4,-3,-2,-1,0...}

x<-5

x={-6,-7,-8,-9,-0...}

Numbers equal to or less than -8 are also less than -5

Hope it helps ;) ❤❤❤

6 0
3 years ago
Read 2 more answers
The variable z varies jointly with x and y and inversely with v and w. Using the constant of variation,k, from the last problem,
antiseptic1488 [7]

Answer:

Step-by-step explanation:

5 0
3 years ago
70 points and i’ll give brainliest!! please answer all the questions on the page! must show work and how you got the answer. ple
Bezzdna [24]

6. One variable only so pretty straightforward.

length-x+4

width-x

x+x+4=80

2x=76

x=38

x+4=42

answer: length 42cm and width 38cm

7. Another money problem!

n-# of nickels

q-# of quarters

n=3+q

0.05n+0.25q=2.85

Substitution works like a charm!

0.05(3+q)+0.25q=2.85

0.15+0.05q+0.25q=2.85

0.3q=2.7

q=9

n=3+q

n=3+9

n=12

answer: 9 nickels and 12 quarters

8. One variable situation again.

Ann's money-2b+9

Betty's money-b

b+2b+9=60

3b=51

b=17

2b+9=43

answer: Ann has $43 and Betty has $17.

9. # of red m&m's-x+1

# of blue m&m's-x

x+1+x=13

x=6

x+1=7

answer: 6 blue and 7 red m&m's

10. a-number of adult tickets

s-number of student tickets

a+s=785 ----> a=785-s

5a+2s=3280

5(785-s)+2s=3280

-3s=-645

s=215

a+s=785

a+215=785

a=570

answer: 215 children tickets and 570 adult tickets

3 0
3 years ago
Punctele O, A, B, C sunt coliniare în această ordine, iar segmentele OA, AB și BC au lungimile exprimate în cm, prin numere natu
julia-pushkina [17]

Răspuns:

a) OC = 18cm

b) MN = 6cm

Explicație pas cu pas:

Găsiți diagrama la întrebarea atașată.

a) Din diagramă se poate observa că OC = OA + AB + AC

OC = 2n + 2n + 2 + 2n + 4

OC = 6n + 6

Următorul este să obțineți valoarea lui n:

OM = OA + AM

Să obținem segmentul AM;

Deoarece M este segmentul mijlociu al AC, atunci;

AM = AC / 2

AM = AB + BC / 2

AM = 2n + 2 + 2n + 4/2

AM = 4n + 6/2

AM = 2n + 3

Din moment ce OM = OA + AM

OM = 2n + 2n + 3

OM = 4n + 3

Dat fiind OM = 11

11 = 4n + 3

4n = 11-3

4n = 8

n = 2

Următorul pas este să calculați OC;

OC = 6n + 6

OC = 6 (2) + 6

OC = 18

Prin urmare, lungimea segmentului OC este de 18 cm

b) Această întrebare ne cere să găsim segmentul de linie MN.

Din diagramă, MN = AM - AN

Deoarece AM = 2n + 3 din întrebarea 1;

AM = 2 (2) +3

AM = 4 + 3

AM = 7

Acum, să obținem AN:

Din diagramă, AN = ON-OA și ON = OB / 2

AN = OB / 2 - OA

AN = (2n + 2n + 2) / 2 - 2n

AN = 4n + 2/2 - 2n

AN = 2n + 1 - 2n

AN = 2n-2n + 1

AN = 1

De la MN = AM - AN

MN = 7 - 1

MN = 6cm

Prin urmare, distanța dintre N, mijlocul segmentului OB și punctul M este de 6cm

6 0
3 years ago
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