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Anna [14]
3 years ago
7

What is the rate of change from 2 gallons to 4 gallons? Pls I need help!!

Mathematics
1 answer:
Tema [17]3 years ago
4 0

Answer:

2 gallons

Step-by-step explanation:

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Use a power of ten to estimate the product.<br><br> 9 × 82.4
Papessa [141]

Answer:

1000

Step-by-step explanation:

9 is close to 10

82.9 is close to 100

10*100=1000

6 0
3 years ago
Read 2 more answers
Use the piecewise function below to evaluate the points f(–3), f(0), and f(–1).
ehidna [41]

Given:

The piecewise function is:

f(x)=\begin{cases}9x & \text{ if } x

To find:

The values of f(-3),f(0), f(-1).

Solution:

In the given piecewise function,

f(x)=9x for x and f(x)=x-4 for x\geq -1.

Putting x=-3 in f(x)=9x, we get

f(-3)=9(-3)

f(-3)=27

Putting x=0 in f(x)=x-4, we get

f(0)=0-4

f(0)=-4

Putting x=-1 in f(x)=x-4, we get

f(-1)=-1-4

f(-1)=-5

The required values are f(-3)=27,f(0)=-4,f(-1)=-5.

Therefore, the correct option is D.

6 0
3 years ago
What is the midpoint of a segment whose endpoints are (-12, -7) and (8, -11)
TEA [102]
The midpoint is (-2, -9).

Using the midpoint formula:

(x1+x2/2, y1+y2/2)
(-12+8/2, -7+(-11)/2)
(-4/2, -18/2)
(-2, -9)
7 0
3 years ago
Dominic placed the following pieces of lumber in order from shortest to longest 23 over three 7 and 7/8 7.9 to 68 square root
Nikolay [14]

Answer:

23/3

7 7/8

7.9

Step-by-step explanation:

3 0
3 years ago
Consider a parent population with mean 75 and a standard deviation 7. The population doesn’t appear to have extreme skewness or
Aleks04 [339]

Answer:

a) \bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

b) Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

c) P(\bar X \leq 77)=P(Z

d) See figure attached

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable of interest. We know from the problem that the distribution for the random variable X is given by:

E(X) = 75

sd(X) = 7

We take a sample of n=40 . That represent the sample size

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

Part b

Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

Part c

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X \leq 77)=P(Z

We can us the following excel code: "=NORM.DIST(1.807,0,1,TRUE)"

Part d

See the figure attached.

8 0
3 years ago
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