THIS IS THE COMPLETE QUESTION BELOW;
The weekly salaries of sociologists in the United States are normally distributed and have a known population standard deviation of 425 dollars and an unknown population mean. A random sample of 22 sociologists is taken and gives a sample mean of 1520 dollars.
Find the margin of error for the confidence interval for the population mean with a 98% confidence level.
z0.10 z0.05 z0.025 z0.01 z0.005
1.282 1.645 1.960 2.326 2.576
You may use a calculator or the common z values above. Round the final answer to two decimal places.
Answer
Margin error =210.8
Given:
standard deviation of 425
sample mean x=1520 dollars.
random sample n= 22
From the question We need to to calculate the margin of error for the confidence interval for the population mean .
CHECK THE ATTACHMENT FOR DETAILED EXPLANATION
Answer:
sorry I don't have learned this much and I am grade 9 student
18,225 :) have a nice day!
Not the whole answer but hope it helps. We know the length of one side and two inner angles. The equivalent of all the inner angles is 180° if you do 68°+56°=124° . Then if you subtract the 124° and 180° you get 56° . That means that you have two equal angles laying under the sides of the triangle. That means that the sides are equal. If the sides are equal that means that the other side is also 1.3 and that will help you get to the final aka CA