a. Find the probability that an individual distance is
greater than 214.30 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (214.30 – 205) / 8.3
z = 1.12
Since we are looking for x > 214.30 cm, we use the
right tailed test to find for P at z = 1.12 from the tables:
P = 0.1314
b. Find the probability that the mean for 20 randomly
selected distances is greater than 202.80 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (202.80 – 205) / 8.3
z = -0.265
Since we are looking for x > 202.80 cm, we use the
right tailed test to find for P at z = -0.265 from the tables:
P = 0.6045
c. Why can the normal distribution be used in part (b),
even though the sample size does not exceed 30?
I believe this is because we are given the population
standard deviation sigma rather than the sample standard deviation. So we can
use the z test.
Answer:
6 months
Step-by-step explanation:
60,120,180,240,300,360
150+35=185. 185,220,255,290,325,360
Answer: 16
Step-by-step explanation:
pls give brainliest
The answer is incorrect. 142 / 3 equals forty-seven with a remainder of one, and the question is saying it equals fifty-two with a remainder of four and asking whether it is true or false. If it’s the R part you’re confused about, R means remainder, or the amount left behind when the division problem is solved. Hope this helped!
Answer:
$3222 in total; $322 more than the original price.
Step-by-step explanation:
For 36 months you pay a total of 36* 89.5=3222.0
Downpayment was 100
Total payment made= 3222+100=3322.
You would pay 3222-2900=$322 higher than normal.
