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leva [86]
3 years ago
7

How do I do 6, 7, 8, 9 and 10?

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
8 0
I’m pretty sure it’s length times width times height but don’t quote me on that
kompoz [17]3 years ago
6 0

Answer:

i think u have to mutiply

Step-by-step explanation:

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PLEASE HELP LIKE NOW IM TIMED.. WILL GIVE BRAINLIEST!!! In the figure, ΔABC ~ ΔDEF. Solve for x. Triangles ABC and DEF. Angles B
VLD [36.1K]
Use CPCTC
Congruent Parts of a Congruent Triangle are Congruent

∠B ≅ ∠E
AB <span>≅ DE
BC </span><span>≅ EF

AB = 20
BC = 24
EF = 6
DE = x

20/24 = x/6

Solve for x, cross multiply

24(x) = 20(6)
24x = 120
24x/24 = 120/24
x = 120/24
x = 5

x = 5, or A is your answer

hope this helps</span>
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4 years ago
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Answer:

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Step-by-step explanation:

The ray is name from the point to the arrow

XY→

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Answer:

If AB = CD, then CD = AB.         symmetric property

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Step-by-step explanation:

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Step-by-step explanation:

7 0
3 years ago
A food packet is dropped from a helicopter and is modeled by the function f(x) = −15x2 + 6000. The graph below shows the height
melisa1 [442]

General Idea:

Domain of a function means the values of x which will give a DEFINED output for the function.

Applying the concept:

Given that the x represent the time in seconds, f(x) represent the height of food packet.

Time cannot be a negative value, so

x\geq 0

The height of the food packet cannot be a negative value, so

f(x)\geq 0

We need to replace -15x^2+6000 for f(x) in the above inequality to find the domain.

-15x^2+6000\geq 0 \; \;  [Divide \; by\; -15\; on\; both\; sides]\\ \\ \frac{-15x^2}{-15} +\frac{6000}{-15} \leq \frac{0}{-15} \\ \\ x^2-400\leq 0\;[Factoring\;on\;left\;side]\\ \\ (x+200)(x-200)\leq 0

The possible solutions of the above inequality are given by the intervals (-\infty , -2], [-2,2], [2,\infty ). We need to pick test point from each possible solution interval and check whether that test point make the inequality (x+200)(x-200)\leq 0 true. Only the test point from the solution interval [-200, 200] make the inequality true.

The values of x which will make the above inequality TRUE is -200\leq x\leq 200

But we already know x should be positive, because time cannot be negative.

Conclusion:

Domain of the given function is 0\leq x\leq 200

4 0
4 years ago
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