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Hoochie [10]
3 years ago
5

Name each rayCalculation Tip: In ray "AB", A is the endpoint of the ray.

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
7 0
There is a ray XY because X is the endpoint of ray XY.

Hope it helps..
Vanyuwa [196]3 years ago
3 0

Answer:

XY→

Step-by-step explanation:

The ray is name from the point to the arrow

XY→

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The mass of a marine organism, in pounds, p years after it is born is given by the polynomial function R(p)=−4p2+300p. Find the
masha68 [24]

Answer:

R(p) = -4p^2 + 300p when p=20.

R(p) = -4(20)^2 + 300(20)

R(p) = -1600 + 6000

R(p) = 4400

The mass when p=20 years is 4400.

8 0
3 years ago
Perimeter of a triangle with side length of 13.9in,10.4,8.5in
AlladinOne [14]

Perimeter =a+b+c

13.9 + 10.4 + 8.5 =

32.8 in (perimeter)


6 0
3 years ago
Read 2 more answers
What is the solution for -10 < x - 9?
krek1111 [17]

Answer:

-1 < x

Step-by-step explanation:

-10 < x - 9

+9. +9

-1 < x

6 0
3 years ago
AREA, PERMITER AND VOLUME QUESTIONS.
castortr0y [4]

Answer:


Step-by-step explanation:

(A) The radius of the circle is=1.8m

Then  diameter will be: 2r=2{\times}1.8=3.6 m

Circumference of circle= {\pi}d=3.14{\times}3.6=11.304 m

Area of the circle={\pi}r^{2}=3.14{\times}(1.8)^{2}=10.17 m^{2}

(B) The area of the rectangular backboard of basketball court = 18900cm^{2}

Width=180cm

Area of rectangle= l{\times}b[/tex]

18900=l{\times}180[/tex]

l=105 cm=1.05m

Perimeter of the seating space=2(l+b)

=2(32.5+18.4)

=101.8 m

Perimeter of the basketball court=2(l+b)

=2(15+28)

=86 m

Now, total perimeter= perimeter of the basketball court+perimeter of the seating space.

Total perimeter=101.8+86=187.8 m

Area of the seating space=l{\times}b

=32.5{\times}18.4=598 m^{2}

(C) The shape consists of one square and 4 triangles, therefore area of square= (side)^{2}=(3)^{2}=9 m^{2}

Area of 4 triangles=4{\times}(\frac{1}{2}{\times}B{\times}H)

=4{\times}(\frac{1}{2}{\times}3{\times}2)=12m^{2}

Area of the shape= Area of the square+ area of the 4 triangles

=9+12=21m^{2}

(D) Perimeter of rectangle with length=40 m (After converting cm to m) and breadth= 10 m is given by: 2(l+b)=2(40+10)=100 m

Perimeter of rectangle with length 68 m and breadth=33 m is given by:2(l+b)=2(68+33)=202 m

Perimeter of  the semicircle=\frac{{\pi}d}{2}=\frac{3.14{\times}34}{2}=53.38 m

Total perimeter= 100+201+53.38=355.38 m

Area of rectangle with length=40 m (After converting cm to m) and breadth= 10 m is given by:l{\times}b=40{\times}10=400 m^{2}

Area of rectangle with length 68 m and breadth=33 m is given by:l{\times}b=68{\times}33=2244 m^{2}

Area of the semi circle=\frac{{\pi}r^{2}}{2}=\frac{3.14{\times}17^{2}}{2}=453.73 m^{2}

Total  area= 400+2244+453.73=3097.73 m^{2}

8 0
3 years ago
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Find a9 in the arithmetic sequence with a1=-2.75 and d=0.25
AleksAgata [21]
A9=A1+(n-1)
-2.75+(8*0.25)
-2.75+2=-0.75
3 0
3 years ago
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