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vfiekz [6]
2 years ago
8

N is an odd number.

Mathematics
1 answer:
Alex777 [14]2 years ago
6 0

Answer:

A and E

Step-by-step explanation:

substitute and odd number into every equation :)

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PLEASE HELP!
Igoryamba
Hello! $200 is the fixed amount. B doesn't have 200 as part of the problem, so B is eliminated. A is also out, because you add, not subtract. 100 is the amount of boots made, not the amount made per pair of boots. 100 would be the value of "x". The cost per day is $9,200, and 9,200 - 200 is 9,000. With 100 pairs of boots being made each day, 9,000/100 is 90. It would cost $90 per pair of boots made, with the variable "x" being beside it. The correct equation would be C(x) = 90x + 200. The answer is D.
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Tomika owns 3/5 of a law partnership. What percent of the partnership does she own
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3 divided by 5 = 0.6%
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Which has a mass of about 10 kilograms?<br><br> Watermelon<br> Pencil<br> Car<br> Apple
Zolol [24]

Answer:

watermelon ..........................................

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2 years ago
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Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

5x-3y+2z=13

and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

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3 years ago
Help me please this is due today
matrenka [14]

Answer:

LCM = 20, GCF = 9

Step-by-step explanation:

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