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shusha [124]
3 years ago
5

The point (4, 10) is in each scatterplot. In which one is it an outlier? On a graph, points (4, 10) and (6, 1) are outside of th

e cluster. On a graph, points are scattered. On a graph, point (2, 1) is outside of the cluster. On a graph, all points are within the cluster.
Mathematics
1 answer:
Trava [24]3 years ago
5 0

2,1 I think I hope this helps

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Which of the following is the measure of side a?<br> 23.3<br> 144<br> 8<br> 16
jenyasd209 [6]

Step-by-step explanation:

it is a right-angled triangle, so the side lengths need to fulfill the Pythagoras rule :

c² = a² + b²

where c is the Hypotenuse, the baseline opposite of the 90 degree angle. and a and b (often called legs) are the sides "enclosing" the 90 degree angle.

so, we have

20² = a² + 12²

400 = a² + 144

a² = 256

a = 16

FYI - we could have picked the right answer also by eliminating the wrong given answer options.

as this is a right-angled triangle :

a cannot be longer than the baseline (20).

that eliminates already the first 2 options.

and then look at the picture : a cannot be shorter than b (the other side line (12)).

that eliminates the third option.

4 0
2 years ago
INT1 4.1.1 Line of Best Fit (classwork)
Lorico [155]

Answer:

a. 2401.06

b. 37.54%

c. 56.3%

Step-by-step explanation:

hopefully this is right

*note: I think you forgot to convert 4-2 back into yards.

a. Robbie's field of view to the North end includes parts not on the football field. so to find the area of the football field he can see, we need to find:

total area of what Robbie sees - area of non football field Robbie sees

what you shaded represents the total of what Robbie sees. it's a triangle. area of a triangle is 1/2(b)(h) where h is distance away and b is width of view.

total area = 1/2(170)(30.92) = 2628.56 yd

area of non football field (pipe to South end)

= 1/2(50)(9.1) = 227.5

so 2628.56 - 227.5 = 2401.06

b. area found in part a / total area of football field

2401.06 / (120*53.3) = .3754

.3754 * 100 = 37.54%

c. the chance of Robbie seeing the touchdown depends on how much of the (North) endzone he can see.

area of north endzone is

10 * 53.3 = 533.

area Robbie sees in endzone is

2628.56 - 2328.48 = 300.08

(found by total area Robbie sees - area of non endzone Robbie sees)

300.08 / 533 = 0.563

= 56.3%

7 0
3 years ago
At 3:30 p.m., Berto’s train was 34 miles past the egg farm, traveling at an average speed of 85 miles per hour. At the same time
timurjin [86]

E=egg farm

x=distantce between  the Berto´s trains and the meeting point.

t=time where the trains meet up

⇒110 miles/h                                          ⇒85miles/h

[---------------------------E----------------------]-------------------------------------X

[............12 miles.......][........34 miles.....][------------ x ----------------------]

distance between Berto´s train and Eduardo´s train=

=12 miles+34 miles=46 miles.

S=d/t      ⇒d=S*t

S=seed

d=distance

T=time

Eduardo´s train;

46 miles+x=t*110 miles/h  ⇒x=t*110 miles/h-46 miles  (1)

Berto´s train;

x=t*85 miles/h  (2)

With the equations (1) and (2) we suggest this system equations:

x=t* 110 miles/h-46 miles

x=t*85 miles/h

we solve this system equiations :

t*110 miles/h-46 miles=t*85 miles/h

110t miles/h-85t miles/h=46 miles

25 t miles/h=46 miles

t=46 miles/25 miles/h=1,84 hour  (≈1 hour, 50 minutes, 24 seconds)

x=t*85 miles/h=156,4 miles

Solution: 1,84 hour

3 0
3 years ago
Read 2 more answers
Angie read 22 pages during a 30-minute study hall. At this rate, how many pages would she read in 45 minutes
frosja888 [35]
45 minutes is equal to 1.5 times 30:

1.5*30=45

so she will also read 22*1.5 pages, which is 22+11=33

so she will read 33 pages
4 0
3 years ago
Edwin built a picture frame 13 inches long and 10 inches wide out of wood that is 2 inches wide.
SSSSS [86.1K]
D is the correct a answer
8 0
2 years ago
Read 2 more answers
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