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3 years ago

The scatter plot shows the weight and fuel efficiency for each of 24 vehicles. Also shown is the line of best fit for the data.

Mathematics

1 answer:

Mandarinka [93]3 years ago

3 0

Answer:

Step-by-step explanation:what are the answers inside the boxes

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three friends bought several packages of football trading cards. each package contains 8 cards. the friends split the cards equa

cluponka [151]

8p=24 and if you do 24/8 you are going to have 3 which means p=3

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4 years ago

Oceanside Bike Rental Shop charges a 14 dollar fixed fee plus 6 dollars an

babunello [35]

68 - 14 = 54, 54/6 = 9 hours

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4 years ago

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Barbara charges $3.50, plus $2.25 for each hour she babysits. If Barbara charges $21.50, how many hours does she babysit?

MAVERICK [17]

Answer:

8 hours

Step-by-step explanation:

The equation is 2.25X + 3.50 = 21.50

X represents the unknown amount of hours she worked. 2.25 is the cost per hour. 3.50 is the fee she charges for every gig. That fee only happens once a gig so naturally it wasn't the number x was placed with.

2.25X + 3.50 = 21.50

2.25X + 3.50 - 3.50 = 21.50 - 3.50

2.25X = 18

2.25X = 18

2.25 2.25

X = 8

8 0

3 years ago

. You are interested in the amount of time teenagers spend weekly working at part-time jobs. A random sample of 15 teenagers was

agasfer [191]

Answer:

$t=\frac{147.3-120}{\frac{50}{\sqrt{15}}}=2.115$

Now we can calculate the degrees of freedom

$df=n-1=15-1=14$

If we find a critical value in the t distribution with 14 degrees of freedom who accumulates 0.05 of the area in the right we got $t_{critc}= 1.761$

Since the calculated value is higher than the critical value we have enough evidence to conclude that the true mean is significantly higher than 120 minutes for the average time of part time jobs

Step-by-step explanation:

Information given

$\bar X=147.3$ represent the sample mean for the amount of time spent at part time jobs

$s=50$ represent the sample standard deviation

$n=15$ sample size

$\mu_o =120$ represent the value to check

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We want to analyze if the true mean for the amount of time spent at part time jobs is higher than 120, the system of hypothesis would be:

Null hypothesis: $\mu \leq 120$

Alternative hypothesis: $\mu > 120$

Since we don't know the population deviation the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{147.3-120}{\frac{50}{\sqrt{15}}}=2.115$

Now we can calculate the degrees of freedom

$df=n-1=15-1=14$

If we find a critical value in the t distribution with 14 degrees of freedom who accumulates 0.05 of the area in the right we got $t_{critc}= 1.761$

Since the calculated value is higher than the critical value we have enough evidence to conclude that the true mean is significantly higher than 120 minutes for the average time of part time jobs

4 0

3 years ago

ANSWER THIS QUICK QUESTION FOR 16 POINTS!

denpristay [2]

If you flipped the picture, it would be 60 degrees. But since its not flipped, it could possibly be 120 degrees since all sides are equal as the sides are parallel to each other.

Hope this helps.

4 0

3 years ago

Read 2 more answers