Third party Reimbursement exists the term that describes payment by someone other than the patient for services rendered.
<h3>What is Third party Reimbursement?</h3>
Compensation for services rendered by a third party as opposed to the person receiving the services is referred to as third party reimbursement. When a patient receives treatment, this is most frequently observed in the context of health care, where an insurance company pays the provider of the service. Fee for Service (FFS), Capitation, and Bundled Payments / Episode-Based Payments have historically been the three main types of compensation in the healthcare industry.
Anyone who pays for medical care but is not the patient is said to be making a "third-party payment." This organis1ation could be either public or private. Instead of using insurance premiums to pay healthcare providers, the government uses money from taxes paid by existing workers.
The payer, an insurance company or health agency that is not directly involved in the patient's care and pays the doctor, clinic, or other second-party provider for the treatment or services provided to the first party is the third party (patient).
Hence, Third party Reimbursement exists the term that describes payment by someone other than the patient for services rendered.
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Answer:
a: Calculate the energy required to transport 3 Na+ outside the cell, and that required to transport 2 K+ inside the cell separately as shown below-
Given- [Na ], Ex Cell Na moves from (reactant/origin site) cell to (product/destination site) blood plasma. [Na ], in cell 15
[K ], Ex cell Given- [K*], in Cell 140 mM 2.7 mM Na moves from (reactant/origin site) cell to (product/destination site) blood
# Now, total energy required to simultaneously transport 3 Na+ out and 2K+ inside the cell = energy required for (3Na+ transport + 2 K+ transport)
= 36.15 kJ mol-1 + 8.00 kJ mol-1 = 44.00 kJ mol-1
b: Enthalpy of ATP hydrolysis = -30.5 kJ mol-1
That is, Energy released from hydrolysis of 1 mol ATP = 30.5
Conclusion: Since the energy released from hydrolysis of 1 mol ATP is LESSER than that of the energy required for simultaneous transport of (3Na+ transport + 2 K+ transport), the hydrolysis of a single mol ATP is NOT sufficient to drive the Na+-K+ pump under given conditions.
Answer: 30 meq
Explanation:
We know that 1 gallon = <u>3.785 Litres</u>
1 litre = <u>1000 milliliters</u>
1 gallon = <u>3785 ml</u>
<u>Concentration = weight/volume </u>
= 565/3785
= 0.149 g/ml
= 149 mg/ml
Multiplying with 15 ml we get
= 149*15 = <u>2235 mg</u>
<u>The atomic weights of:</u>
Potassium (K) = 39
Chlorine (Cl) = 35.5
Finding the equivalent weight of Kcl = 39 + 35.5 = 74.5
So, 1 equivalent of KCl is 74.5 g
= 2235 mg * 1 meq/74.5 mg = 30 meq K+
Therefore, there are 30 milliequivalents of K in 15 ml of this solution
