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GalinKa [24]
3 years ago
15

How do hydroelectric dams emit greenhouse gases like methane without burning any fossil fuels?

Biology
1 answer:
Feliz [49]3 years ago
4 0

Answer:

Rather than combusting fossil fuels, like coal, oil, or natural gas, which put over 52 million kilotons of greenhouse gases into the atmosphere each year, dams block the water flowing in rivers or lakes and use the force of the would-be flow to turn turbines.

Explanation:

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Which of the following best describes a benefit of one type of nonrenewable energy? (2 points)
KIM [24]
Natural gas and petroleum, upon burning, produce carbon dioxide. If you look at methane and the such, these hydrocarbons react with oxygen forming carbon dioxide and water.

The claim that petroleum is not carbon based is downright wrong. Methane is a hydrocarbon, and petroleum is a combination of complex hydrocarbons with varying chains of carbon atoms, some having 6 carbon atoms, others 60, giving it the viscous feel.

Coal deposits may be found in many places, but are still scarce and poses A LOT of risks, for example children were often harmed during the Industrial Revolution as a result of breathing in too much of the dirty air. Even now, coal mining is not without risk.

The only right answer then is the last one, where nuclear power does not produce air pollution. It relies on nuclear fission, where upon the splitting of uranium atoms they release energy, and this energy is harnessed by scientists for the betterment of all.
8 0
3 years ago
In gorillas, the ability to roll the tongue is under the control of 1 gene. The R allele, which confers tongue-rolling ability,
aalyn [17]

Answer:

0.4550

Explanation:

In this example, R allele is dominant, so individuals RR and Rr can roll their tongues. If in a population of 1000 gorillas, there are 575 gorillas who can roll their tongues, they will be RR and Rr.

In this case, there is Hardy Weinberg Equilibrium, so the following will be true:

p^{2}+2pq+q^{2}=1

Where:

p^{2}= frequency of RR

2pq= frequency of Rr

q^{2}= frequency of rr

The question is what is the frequency of heterozygotes, or, what is the value of 2pq.

We know that RR+Rr is 575 individuals in a population of 1000, or 0.575.

In other words:

p^{2}+2pq=0.575

So, it is possible to find q^{2}:

q^{2}= 1-2pq-p^{2}  \\q^{2}=1-(0.575)\\q^{2}=0.425

Now, there are two alleles in the population, so the following will be true:

p+q=1

It is possible to find q  (the frequency of allele r) and p (the frequency of allele p):

q=\sqrt{q^{2} }\\ q=\sqrt{0.425} \\q=0.652

Therefore:

p=1-q\\p=1-0.652\\p=0.348

Now, the frequency of heterozygotes or 2pq is:

2pq=2*0.652*0.348\\2pq=0.45

7 0
3 years ago
Why are scientific explanations subject to change?
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3 years ago
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Dahasolnce [82]

Answer:

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4 years ago
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