Using the distance formula;
![|d|=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=%7Cd%7C%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
From the points given:
x₁=-1 y₁=-2 x₂=8 y₂=10
substitute the values into the formula;
![|d|=\sqrt[]{(8+1)^2+(10+2)^2}](https://tex.z-dn.net/?f=%7Cd%7C%3D%5Csqrt%5B%5D%7B%288%2B1%29%5E2%2B%2810%2B2%29%5E2%7D)
![=\sqrt[]{9^2+12^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B9%5E2%2B12%5E2%7D)
![=\sqrt[]{81+144}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B81%2B144%7D)
![=\sqrt[]{225}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B225%7D)

The distance is 15 units.
For this case we have that by definition, the slope of a line is given by:

Two points are needed through which the line passes:

Substituting:
Rounding:

Answer:

Hmmm it would be kind of hard to graph as it will be a curved line but the middle of the line would be at (2,-7). Not (-2,-7).
And it will be curving upwards, meaning it will start by going down and end by going up.
Hope this helps some.
Answer: 49.25
Step-by-step explanation: