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3 years ago

Which angles have a greater measure than angle 4 ?

Mathematics

1 answer:

ikadub [295]3 years ago

4 0

Answer:

angels 3,10,11

Step-by-step explanation:exterior angels are larger

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Solve the Inequality. -9-3x > 2(25 + 2x) + 4 The solution is

Kamila [148]

Answer:

x=-9

Step-by-step explanation:

You first multiple 2 and 25 and 2 and 2x. Then the next line should be -9-3x>50+4x+4. After that you add 50 and

4 0

3 years ago

You have a set of cards labeled 1-10. Set A is drawing an even card. Set B is drawing a 8 or higher. What is the P ( A ∪ B ) ?

creativ13 [48]

set A = {2, 4, 6, 8, 10} (only even cards)

set B = {8, 9, 10} (8 or higher)

( A ∩ B ) means the numbers which are common in both sets .

They both have 8 & 10 in common.

So the answer is: P(A ∩ B) = {8,10}

5 0

3 years ago

Find the length of the third side. If necessary, round to the nearest tenth

Lilit [14]

$\huge\bold{Given:}$

Length of the base = 8

Length of the hypotenuse = 17

$\huge\bold{To\:find:}$

The length of the third side '' $x$ ".

$\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}$

$\longrightarrow{\purple{x\:=\: 15}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

Using Pythagoras theorem, we have

(Perpendicular)² + (Base)² = (Hypotenuse)²

$\longrightarrow{\blue{}}$ ${x}^{2}$ + (8)² = (17)²

$\longrightarrow{\blue{}}$ ${x}^{2}$ + 64 = 289

$\longrightarrow{\blue{}}$ ${x}^{2}$ = 289 - 64

$\longrightarrow{\blue{}}$ ${x}^{2}$ = 225

$\longrightarrow{\blue{}}$ $x$ = $\sqrt{225}$

$\longrightarrow{\blue{}}$ $x$ = $15$

Therefore, the length of the missing side $x$ is $15$ .

$\huge\bold{To\:verify :}$

$\longrightarrow{\green{}}$ (15)² + (8)² = (17)²

$\longrightarrow{\green{}}$ 225 + 64 = 289

$\longrightarrow{\green{}}$ 289 = 289

$\longrightarrow{\green{}}$ L.H.S. = R. H. S.

Hence verified.

$\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♨}}}}}$

3 0

2 years ago

Use the Divergence Theorem to evaluate S F · dS, where F(x, y, z) = z2xi + y3 3 + sin z j + (x2z + y2)k and S is the top half of

GenaCL600 [577]

Close off the hemisphere $S$ by attaching to it the disk $D$ of radius 3 centered at the origin in the plane $z=0$ . By the divergence theorem, we have

$\displaystyle\iint_{S\cup D}\vec F(x,y,z)\cdot\mathrm d\vec S=\iiint_R\mathrm{div}\vec F(x,y,z)\,\mathrm dV$

where $R$ is the interior of the joined surfaces $S\cup D$ .

Compute the divergence of $\vec F$ :

$\mathrm{div}\vec F(x,y,z)=\dfrac{\partial(xz^2)}{\partial x}+\dfrac{\partial\left(\frac{y^3}3+\sin z\right)}{\partial y}+\dfrac{\partial(x^2z+y^2)}{\partial k}=z^2+y^2+x^2$

Compute the integral of the divergence over $R$ . Easily done by converting to cylindrical or spherical coordinates. I'll do the latter:

$\begin{cases}x(\rho,\theta,\varphi)=\rho\cos\theta\sin\varphi\\y(\rho,\theta,\varphi)=\rho\sin\theta\sin\varphi\\z(\rho,\theta,\varphi)=\rho\cos\varphi\end{cases}\implies\begin{cases}x^2+y^2+z^2=\rho^2\\\mathrm dV=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi\end{cases}$

So the volume integral is

$\displaystyle\iiint_Rx^2+y^2+z^2\,\mathrm dV=\int_0^{\pi/2}\int_0^{2\pi}\int_0^3\rho^4\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\frac{486\pi}5$