73.085 in standard form
1 answer:
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k =
using the ' laws of logarithms '
log x - log y = log ( )
logx = logy ↔ x = y
logk - log(k - 2) = log5
log ( =log 5
= 5
5(k - 2) = k
5k - 10 = k
4k = 10 ⇒ k = =
k =
using the ' laws of logarithms '
log x - log y = log ( )
logx = logy ↔ x = y
logk - log(k - 2) = log5
log ( =log 5
= 5
5(k - 2) = k
5k - 10 = k
4k = 10 ⇒ k = =