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Debora [2.8K]
3 years ago
5

Maria was foing a assroom survey. She asked the girls in the class how many siblings they had and recorded the results: 1,2,3,6,

7,9,9,9,10. Determine the mean (rounded to the nearest tenth) the median, mode, and range of the results
Mathematics
2 answers:
GenaCL600 [577]3 years ago
6 0

Mean: The sum of all the numbers, divided by the amount of numbers in the set.

56 / 9 = 6.2

Median: The middle value of a set.

7

Mode: The value that occurs most frequently.

9

Range: The highest number of the set subtracted by the lowest number.

10 - 1 = 9

Hope this helps you!


umka21 [38]3 years ago
3 0
Median: 7 because it is in the very middle of the numbers

Mean: add up all the numbers and divide by how many numbers there are. So the mean should be 56÷9=6.2. 6.2(2 is repeating) is the mean

Range: the range is the difference between the highest and lowest numbers. so that means the range is 10-1=9. the range is 9
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3. Solve 2log4y - log4 (5y - 12) = 1/2<br>​
Ilia_Sergeevich [38]

Answer:

y =  4  or y = 6

Step-by-step explanation:

2log4y - log4 (5y - 12) = 1/2

​2log_4(y) - log_4(5y-12) = log_4(2)           apply law of logarithms

log_4(y^2) + log_4(1/(5y-12)) = log_4(/2)    apply law of logarithms

log_4(y^2/(5y-12)) = log_4(2)                     remove logarithm

y^2/(5y-12) = 2                                            cross multiply

y^2 = 10y-24                                                  rearrange and factor

y^2 - 10y + 24 = 0

(y-4)(y-6) = 0

y= 4 or y=6

4 0
3 years ago
Find the length of XY.<br> Imported Asset <br><br> 4<br><br> 8<br><br> 16<br><br> 11.3
kompoz [17]

Answer: 8 (The second option).


Step-by-step explanation:

1. To solve this exercise you draw a line to a point O, this lines will bisect the angle of Z∠60°. Then will obtain two into two right triangles with two angles of 30° at the point Z.

2. The lenght XY will be twice the lengt XO or YO.

3. Let's  calclate XO as following:

sin(30)=\frac{XO}{8}\\XO=4

4. Then, XY is:

XY=2XO\\XY=2*4\\XY=8


7 0
3 years ago
Barry owns a music store, He recorded the sales of a newly launched album as part of his biweekly inventory. The table shows the
dimulka [17.4K]
Hi! Basically, the problem is asking us to find the values of a, b, and c in the equation f(x)=a x^{2} +bx+c. Since we have three unknowns, we just need three equations. We can find these equations by using the data in the table.

First let's plug x = 0 and f(x) = 0.
0=0+0+c
c=0

Now that we know c, it's time to pick two more pairs. Let's plug-in (2,78) and (4,152)

78=4a+2b
152=16a+4b

Before proceeding with the process of eliminating one variable, let us first reduce both equations to their lowest terms. We divide the first equation by 2 and we divide the second one by 4.

39=2a+b
38=4a+b

Next, we subtract equation 2 from equation 1.

1=-2a
a=-0.5

Finally, we substitute the value of a to equation 2 to get the value of b.

38=4(-0.5)+b
b=40

Therefore, the function should be f(x)=-0.5 x^{2} +40x
5 0
3 years ago
Read 2 more answers
Ricky Bobby wants to buy a new automobile for $55,000 in 8 years. How much money must Ricky's original investment be if he makes
laila [671]

Answer:

PV= $40,279.36

Step-by-step explanation:

Giving the following information:

Number of periods= 8*12= 96 months

Interest rate= 0.039/12= 0.00325

Future value (PV)= $55,000

<u>To calculate the initial investment, we need to use the following formula:</u>

PV= FV/(1+i)^n

PV= 55,000 / (1.00325^96)

PV= $40,279.36

4 0
2 years ago
Find the first 5 terms of the arithmetic sequence : a(1)=-3 , a(17)=-20
madreJ [45]
The explicit formula for arithmetic sequence is:
an=a+(n-1)d
where:
a=first term
d=common difference 
given:
a3=22
a(17)=-20
substituting this in our equation we get:
22=a+(3-1)d
22=a+2d
a=22-2d........i

also:
-20=a+(17-1)d
-20=a+16d.....ii
but substituting i in ii we get:
-20=22-2d+16d
-20-22=14d
-42=14d
d=-3
but:
a=22-2d
a=22-2(-3)
a=28
thus the formula will be:
an=28-3(n-1)
thus the first term will be 28
the 2nd term will be:
a2=28-3(2-1)
a2=25

the 3rd term will be:
a3=28-3(3-1)
a3=28-6
a3=22

a4=28-3(4-1)
a4=28-9
a4=15

a5=28-3(5-1)
a5=28-3(4)
a5=28-12
a5=15

5 0
3 years ago
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