Answer:
666
explain the answer step by step
The P(!2)=1-P(2)=1-1/6=5/6
Answer:
If λ is an eigenvalue of A and x is the corresponding eigenvector, then Ax=λx. Now, notice that (A-sI)x=Ax-sx=λx-sx=(λ-s)x. As x is different for zero we can affirm that (λ-s) is an eigenvalue of A-sI and x is the corresponding eigenvector
Step-by-step explanation:
Recall from the definition of eigenvalue: we say that the number (real or complex) λ is an eigenvalue of the matrix A if and only if there is a vector x, different from zero such that Ax=λx.
So, we only need to show that (A-sI)x=(λ-s)x.
Answer:
= 15/4 as fraction
Step-by-step explanation:
