Answer:
C is true also
Step-by-step explanation:
Answer:
Mean = 35
Variance = 291.7
Step-by-step explanation:
Data provided in the question:
X : 1, 2, 3, 4, 5, 6
All the data are independent
Thus,
The mean for this case will be given as:
Mean, E[X] = 
or
E[X] = 
or
E[X] = 3.5
For 10 days, Mean = 3.5 × 10 = 35
And,
variance = E[X²] - ( E[X] )²
Now, for this case of independent value,
E[X²] = 
or
E[X²] = 
or
E[X²] = 
or
E[X²] = 15.167
Therefore,
variance = E[X²] - ( E[X] )²
or
variance = 15.167 - 3.5²
or
Variance = 2.917
For 10 days = Variance × Days²
= 2.917 × 10²
= 291.7
<span>The answer is B. C(n) = 0.75n - 0.25.
Let n be the number of pieces. The price for 1 piece is $0.75. The price C for n pieces without a coupon is n * $0.75: C(n) = 0.75n. The coupon value is $0.25. So, this value must be subtracted from the total price of n pieces. Since the coupon values in independent on the number of pieces, the price C for n pieces with the coupon will be: C(n) = 0.75n - 0.25. Therefore, the correct choice is B.</span>
Answer:
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