Answer:
a)
b)
c)
Step-by-step explanation:
<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.
This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.
Then write the polynomial in factored form.
Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.
<u>For question b, do the same procedure</u>.
Degree: 3
Zeros: -5/2, 4/5, 6.
The factors are
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<u>Finally for the question c we have</u>
Degree: 5
Zeros: -3, 1, 4, -1
Multiplicity 2 in -1
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Yes because they're the same
The slope is 2x. In other words 2/1
2x - 6y = 12
so we pick any number for x and then solve for y
lets say x = 0
2(0) - 6y = 12
-6y = 12
y = -12/6
y = -2....so when x = 0, y = -2....(0,-2) <== one point
lets say x = 1
2(1) - 6x = 12
2 - 6x = 12
-6x = 12 - 2
-6x = 10
x = -10/6
x = - 5/3...so when x = 1, y = -5/3....(1,-5/3) <== another point
Lets say x = 2
2(2) - 6y = 12
4 - 6y = 12
-6y = 12 - 4
-6y = 8
y = -8/6
y = - 4/3....so when x = 2, y = -4/3.....(2,-4/3) <== another point
lets say x = 3
2(3) - 6y = 12
6 - 6y = 12
-6y = 12 - 6
-6y = 6
y = -6/6
y = -1....so when x = 3, y = -1.....(3,-1) <== another point
now there is 4 points.