2 years ago

PLEASE HELP I NEED THE ANSWER -4 -5 -2 4

Mathematics

1 answer:

xxTIMURxx [149]2 years ago

7 0

Answer:

-4 ..... 1.5

-5......0

-2......2.5

4.......8

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Sistema de ecuaciones.5x+2y=-152x-2y=-6

Zolol [24]

Tnemos el sisema de ecuaciones:

$\begin{gathered} 5x+2y=-15 \\ 2x-2y=-6 \end{gathered}$

Podemos resolverlo por eliminación sumando ambas ecuaciones y eliminando y. Asi podemos resolver para x:

$\begin{gathered} (5x+2y)+(2x-2y)=(-15)+(-6) \\ 7x+0y=-21 \\ x=-\frac{21}{7} \\ x=-3 \end{gathered}$

Ahora podemos resolver para y con cualquiera de las dos ecuaciones:

$\begin{gathered} 2x-2y=-6 \\ 2\cdot(-3)-2y=-6 \\ -6-2y=-6 \\ -2y=-6+6 \\ -2y=0 \\ y=0 \end{gathered}$

Respuesta: x=-3, y=0

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Sandra will get 10 pounds

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I am a number less than 3000. When you divide me by 32, my remainder is 30. When you divide me by 58, my remainder 44. What numb

yKpoI14uk [10]

Let Q1 and Q2 be the quotients from dividing 32 and 58 respectively.Then 32 Q1 + 30 = 58 Q2 + 4432 Q1 = 58 Q2 + 1416 Q1 = 29 Q2 + 716 Q1 = (16 + 13)Q2 + 716 Q1 = 16 Q2 + 13 Q2 + 716(Q1 - Q2) = 13 Q2 + 7Because Q1 and Q2 are integers, we have to find Q2 whereby 13Q2 + 7 is divisible by 16.After some try-and-error, we get Q2 = 13. That is 13*13 + 7 = 176Therefore, Q1 - Q2 = 11 --> Q1 - 13 = 11 --> Q1 = 2432*24 + 30 = 58*13 + 44 = 798.I am 798

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3 years ago