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3 years ago

Pls help points and I will mark brainliest

Mathematics

1 answer:

Nutka1998 [239]3 years ago

8 0

Answer:

sorry but do not threat people you said I will mark u the brainliest

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Condense log5 (2y) + log5 (8)

Wittaler [7]

Apply log rule [ $\text{log}_a(xy)=\text{log}_ax+\text{log}_ay$ ] to condense.

$\text{log}_5(2y)+\text{log}_5(8)=\text{log}_5(2y*8)$

→ $\text{log}_5(16y)$ ←

Best of Luck!

4 0

3 years ago

What is the sum of the roots of the quadratic equation x²+6x-14=0?

aivan3 [116]

Answer:

<h3>Sum of Roots =<u> (-8)</u><u> </u><u> </u></h3><h3>Product of Roots = <u> </u><u> </u><u>(-84)</u><u> </u><u> </u></h3>

Step-by-step explanation:

${x}^{2} + 6x - 14 = 0$

Roots :- 6 and -14

Sum of the roots :

[6 + (-14)]

= (-8)//

Product of the roots :

[(6)(-14)]

= (-84)//

8 0

3 years ago

A cup has the shape of a right circular cone. The height of the cup is 12 cm, and the radius of the opening is 3 cm. Water is po

Leviafan [203]

Answer:

The rate at which the water level is rising when the depth of the water in the cup is 5 centimeters is approximately 0.407 centimeters per second.

Step-by-step explanation:

From Geometry, we find that the volume of the cone ( $V$ ), measured in cubic centimeters, is defined by the formula:

$V = \frac{\pi\cdot \cdor r^{2}\cdot h}{3}$ (Eq. 1)

All right circular cone satisfies the following relationship:

$\frac{h}{r} = \frac{h_{max}}{r_{max}}$

$r = \left(\frac{r_{max}}{h_{max}} \right)\cdot h$ (Eq. 2)

Where:

$r$ - Radius of the right circular cone, measured in centimeters.

$h$ - Height of the right circular cone, measured in centimeters.

By applying (Eq. 2) in (Eq. 1), we get the following formula:

$V = \frac{\pi}{3} \cdot \left(\frac{r_{max}}{h_{max}} \right)^{2}\cdot h^{3}$ (Eq. 1b)

Given that $r_{max}$ and $h_{max}$ are constant, we get the rate of change for the volume of the right circular cone ( $\dot V$ ), measured in cubic centimeters per second:

$\dot V = \pi\cdot \left(\frac{r_{max}}{h_{max}} \right)^{2}\cdot h^{2}\cdot \dot h$ (Eq. 2)

Where $\dot h$ is the rate of change of the water level, measured in centimeters per second.

If we know that $\dot V = 2\,\frac{cm^{3}}{s}$ , $r_{max} = 3\,cm$ , $h_{max} = 12\,cm$ and $h = 5\,cm$ , the rate of change of the water level is:

$\dot h = \frac{\dot V}{\pi\cdot h^{2}}\cdot \left(\frac{h_{max}}{r_{max}} \right)^{2}$

$\dot h =\left[\frac{2\,\frac{cm^{3}}{s} }{\pi\cdot (5\,cm)^{2}}\right] \cdot \left(\frac{12\,cm}{3\,cm} \right)^{2}$

$\dot h \approx 0.407\,\frac{cm}{s}$

The rate at which the water level is rising when the depth of the water in the cup is 5 centimeters is approximately 0.407 centimeters per second.

4 0

3 years ago

3) Use the situation to choose the correct answer.

DaniilM [7]

3.60 cg I used a calculator and did 60%(12%x5) of 6

4 0

3 years ago

NEED HELP ASAP!!

ladessa [460]

The answer to this problem is a Horizontal translation of 4 units left and a Vertical translation of 8 units up.

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4 years ago