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Serhud [2]
3 years ago
8

What is the GCF of 28a^3 b and 16ab ? A)4ab B)4a3b C)28ab D)112a3b2

Mathematics
1 answer:
N76 [4]3 years ago
7 0
28a⁴b: 2 · 2 · 7 · a · a · a · a · b
 16ab: 2 · 2 · 2 · 2 · a · b

GCF(28a⁴b, 16ab) = 4ab

The answer is A.
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Question 4 of 30
Gemiola [76]

Answer:

1/36

Step-by-step explanation:

prob of each dice is 1/6

=1/6 * 1/6

6 0
2 years ago
Which statement is true?
seropon [69]

Answer: C. A line that rises from left to right has a positive slope.

Step-by-step explanation: A. has a slope of 0, B. has an undefined slope, and D. is supposed to go left to right not right to left.

6 0
2 years ago
Y=–6x+2<br> –12x – 2y=–4<br> How many solutions does this linear system have?
DerKrebs [107]

The linear equation y = -6x + 2; -12x - 2y = -4 has no solution

<h3>Linear equation</h3>

y = -6x + 2

-12x - 2y = -4

  • Substitute y = -6x + 2 into (2)

-12x - 2y = -4

-12x - 2(-6x + 2) = -4

-12x + 12x -4 = -4

-12x + 12x = - 4 + 4

0 = 0

  • Solve for x

y = -6x + 2

y - 2 = -6x

x = (y - 2) / -6

  • Substitute into (2)

-12x - 2y = -4

-12(y- 2)/ 6 - 2y = -4

(-12y + 24) / 6 - 2y = -4

-2y + 4 - 2y = 4

0 = 0

Learn more about linear equation:

brainly.com/question/4074386

#SPJ1

3 0
1 year ago
John ordered a large three topping pizza for $7. 50 and a large 8 topping pizza for $10. Write an equation in slope-intercept fo
yKpoI14uk [10]

to get the equation of any straight line, we simply need two points off of it, well, let's use the provided values hmmm

\begin{array}{ccll} \stackrel{toppings}{x}&\stackrel{cost}{y}\\ \cline{1-2} 3 & 7.50\\ 8& 10 \end{array} \qquad\implies \qquad (\stackrel{x_1}{3}~,~\stackrel{y_1}{7.50})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{10}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{10}-\stackrel{y1}{7.50}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{3}}}\implies \cfrac{2.5}{5}\implies \cfrac{~~ \frac{25}{10}~~}{5}\implies \cfrac{25}{50}\implies \cfrac{1}{2}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7.50}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{3})\implies y-\cfrac{750}{100}=\cfrac{1}{2}(x-3) \\\\\\ y-\cfrac{15}{2}=\cfrac{1}{2}x-\cfrac{3}{2}\implies y=\cfrac{1}{2}x-\cfrac{3}{2}+\cfrac{15}{2}\implies y=\cfrac{1}{2}x-6

3 0
1 year ago
HELPPP PLEASE HELP ASAPPP
34kurt

Answer:

okay just call my personal phone number it is (911) i hope that it make u feel better

7 0
2 years ago
Read 2 more answers
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