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Ronch [10]
3 years ago
14

What is the period of the function f(x) shown in the graph? Enter your answer in the box.

Mathematics
1 answer:
muminat3 years ago
4 0

Answer:

Step-by-step explanation:

π

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Suppose the weights of tight ends in a football league are normally distributed such that σ2=1,369. A sample of 49 tight ends wa
Darya [45]

Answer:

Step-by-step explanation:Answer Explanation

Correct answers:

$\left(241.42,\ 262.14\right)$

A 95% confidence interval for μ is (x¯−zα/2σn‾√,x¯+zα/2σn‾√). Here, α=0.05, σ=37, and n=49. Use Excel to calculate the 95% confidence interval.

1. Open Excel, enter the given data in column A, and find the sample mean, x¯, using the AVERAGE function. Thus, the sample mean, rounded to two decimal places, is x¯=251.78.

2. Click on any empty cell, enter =CONFIDENCE.NORM(0.05,37,49), and press ENTER.

3. The margin of error, rounded to two decimal places, is zα/2σn‾√≈10.36. The confidence interval for the population mean has a lower limit of 251.78−10.36=241.42 and an upper limit of 251.78+10.36=262.14.

Thus, the 95% confidence interval for μ is (241.42, 262.14).

6 0
3 years ago
A park ranger would like to clear more than 10 miles of trail. So far, he has cleared 2 miles. From now on, he can clear 3/4 mil
Scilla [17]
It would take 7:30 minutes to clear the rest of the 10 miles.
6 0
3 years ago
Someone help me please, 25 points
ycow [4]
A. (x+8)^ 2 + 1
B. (x-3)^ 2 - 8
C. ( x - 3/2) ^ 2 - 1/4
4 0
2 years ago
Help me<br> Pls its due soon and i have no clue how to do this
Alekssandra [29.7K]

Question 10

Draw a 30-60-90 triangle template. Refer to the diagram below.

We have 1 as the short leg, 2 as the hypotenuse and sqrt(3) as the long leg.

Place the angle theta as the reference angle such that it's opposite the sqrt(3) side.

That allows tan(theta) = sqrt(3)/1 = opposite/adjacent

In other words, tan(60) = sqrt(3)/1

So theta = 60 is one solution. We add on 180 to get the other solution. So the other solution is 60+180 = 240

So tan(60) = tan(240) = sqrt(3)

<h3>Answers:  60 and 240</h3>

======================================================

Question 11a

sin(theta) = -0.8

theta = arcsin(-0.8) or theta = 180-arcsin(-0.8)

theta = -53.1301  or theta = 180 - (-53.1301)

theta = -53.1301  or theta = 233.1301

Add 360 to the first angle to find a coterminal angle counterpart.

-53.1301 + 360 = 306.8699

So the two approximate solutions are

theta = 306.8699  or theta = 233.1301

and those round to 306.9 and 233.1 respectively.

<h3>Answers:  233.1 and 306.9 </h3>

======================================================

Question 11b

cot(theta) = 1.8

tan(theta) = 1/(1.8)

theta = arctan( 1/(1.8) )  or theta = 180+arctan( 1/(1.8) )

theta =  29.0546 or theta = 180+29.0546

theta = 29.0546 or theta = 209.0546

theta = 29.1 or theta = 209.1

<h3>Answers:  29.1  and 209.1</h3>

6 0
3 years ago
During which phase were no faults introduced?
dybincka [34]

Step-by-step explanation:

phase 4 had no faults introduced

4 0
2 years ago
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