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Ronch [10]
3 years ago
14

What is the period of the function f(x) shown in the graph? Enter your answer in the box.

Mathematics
1 answer:
muminat3 years ago
4 0

Answer:

Step-by-step explanation:

π

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PLEASE HELPPP i would really appreciate it :)
qaws [65]

Answer:

Y = - 12.55X1 + 276.52

Step-by-step explanation:

Given the data:

Age of child :(X) : 4, 6, 10, 13, 14, 17

Time (seconds) (Y) : 230, 205, 132, 119, 108, 62

Using technology, the linear regression equation obtained using the data Given is :

Y = - 12.55X1 + 276.52

Where :

Slope = - 12.55

Intercept = 276.52

This also indicates that a negative slope is present and hence a negative relationship between age of Child and time in seconds.

3 0
2 years ago
-1(-2x + 4) = 6<br><br> Hellooooooooooo
butalik [34]

Answer:

x=5

Step-by-step explanation:

First we distribute

2x-4=6

isolate x

2x=10

divide both sides by 2

x=5

(plz give brianliest ty)

6 0
3 years ago
Read 2 more answers
Witch is greater 6.41 or 6.38
bearhunter [10]

Answer:

6.41

Step-by-step explanation:

if u subtract 6.38 from 6.41  you have .03 left over.

4 0
2 years ago
Read 2 more answers
the ratio of dogs to cats at the pet store is 1:4.if the pet shop has 7 dogs,how many cats does it have ?
slamgirl [31]
1:4=\frac{1}{4}\\\\d-number\ of\ dogs;\ c-number\ of\ cats\\\\d:c=1:4\to\frac{d}{c}=\frac{1}{4}\\\\d=7\ therefore\\\\\frac{7}{c}=\frac{1}{4}\ \ \ \ |cross\ multiply\\\\1\cdot c=7\cdot4\\\\\boxed{c=28}\leftarrow answer
6 0
2 years ago
Find the exact value of cos theta​, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.
vova2212 [387]

Answer:

cos \theta = -\frac{8}{17}

Step-by-step explanation:

For this case we know that:

sin \theta = \frac{15}{17}

And we want to find the value for cos \theta, so then we can use the following basic identity:

cos^2 \theta + sin^2 \theta =1

And if we solve for cos \theta we got:

cos^2 \theta = 1- sin^2 \theta

cos \theta =\pm \sqrt{1-sin^2 \theta}

And if we replace the value given we got:

cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

cos \theta = -\frac{8}{17}

5 0
2 years ago
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