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Dmitrij [34]
3 years ago
9

What is a document you can create with word-processing software

Computers and Technology
1 answer:
madam [21]3 years ago
6 0

Answer:

Word processing software can easily create, edit, store, and print text documents such as letters, memoranda, forms, employee performance evaluations (such as Appendix A), proposals, reports, security surveys (such as Appendix B), general security checklists, security manuals, books, articles, press releases, and ... I think the answer is this

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A(n) _____ exists when there are functional dependencies such that XY is functionally dependent on WZ, X is functionally depende
Nat2105 [25]

A partial dependency exists.

We have two types of dependency. The partial dependency and the transitive dependency.

The answer here is partial dependency. It occurs when the attribute only depends on some parts of the element. In such attribute, the primary key is the determinant.

It can be shown as;

XY→WZ , X→W and XY is the primary key or the only candidate key

Read more at brainly.com/question/9588869?referrer=searchResults

3 0
3 years ago
Read 2 more answers
You develop an app, and you don't want anyone to resell it or modify it. This is an example of: A an operating system. B open so
Mars2501 [29]
The answer is C. Proprietary software is when the publisher reserves rights from licensees to modify or share the software.
5 0
3 years ago
Read 2 more answers
Explain the principles of computer applications ​
9966 [12]

Answer:

The nature of computers and code, what they can and cannot do.

How computer hardware works: chips, cpu, memory, disk.

Necessary jargon: bits, bytes, megabytes, gigabytes.

How software works: what is a program, what is "running"

How digital images work.

Computer code: loops and logic.

Big ideas: abstraction, logic, bugs.

3 0
3 years ago
Does a triangle with sides of lengths 1.5 ft, 2.5 ft, and 2 ft form a right triangle? How do you know?
timama [110]

Answer:

Yes, the side lengths of 1.5, 2.5, and 2 ft form a right triangle.

Explanation:

Before we solve this problem, we need to know a couple of things.

In a right triangle, you have two legs and a diagonal line that goes from one leg to the other or from one side to the other. This line is called the hypotenuse. It is the longest side of a right triangle. This length can be calculated by using a special formula that is over a thousand years old.

The formula is called the Pythagorean Theorem.

The formula states that if you square one leg and the other leg and add it up. You get the side of hypotenuse which is squared as well.

Here it is in simple terms: a^{2} +b^{2} =c^{2}.

a and b are your two legs.

C is your hypotenuse.

In this case 1.5 and 2 are your legs and 2.5 is your hypotenuse since it is the longest side.

Before we calculate, there is a converse to the Pythagorean Theorem.

If a^{2} +b^{2} \neq c^{2}, then it is not a right triangle.

Lets make 1.5 for a

and 2 for b.

We know 2.5 is for c.

Here it is.

1.5^{2} +2^{2} =2.5^{2}. The / means it is a fraction.

1.5 squared is 9/4 and 2 squared is 4. Add 4 and 9/4 and you get 25/4 squared. Take the square root of 25/4 and you get 5/2.

5/2 is equal to 2.5, so the Pythagorean Theorem applies to this triangle. Therefore, these side lengths do form a right triangle.

Hope this helps!

3 0
3 years ago
) Consider a router that interconnects four subnets: Subnet 1, Subnet 2, Subnet 3 and Subnet 4. Suppose all of the interfaces in
erik [133]

Answer:

Check the explanation

Explanation:

223.1.17/24 indicates that out of 32-bits of IP address 24 bits have been assigned as subnet part and 8 bits for host id.

The binary representation of 223.1.17 is 11011111 00000001 00010001 00000000

Given that, subnet 1 has 63 interfaces. To represent 63 interfaces, we need 6 bits (64 = 26)

So its addresses can be from 223.1.17.0/26 to 223.1.17.62/26

Subnet 2 has 95 interfaces. 95 interfaces can be accommodated using 7 bits up to 127 host addresses can represented using 7 bits (127 = 27)

and hence, the addresses may be from 223.1.17.63/25 to 223.1.17.157/25

Subnet 3 has 16 interfaces. 4 bits are needed for 16 interfaces (16 = 24)

So the network addresses may range from 223.1.17.158/28 to 223.1.17.173/28

4 0
3 years ago
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