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Degger [83]
3 years ago
11

PLEASE HELP WITH THIS!

Physics
1 answer:
jok3333 [9.3K]3 years ago
7 0

Answer: A

Explanation:

Parallel circuit. The source current is three times the current of a single bulb

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How does the nuclear charge relate to the energy of the 1s orbital?
nlexa [21]

Explanation:

Effective nuclear charge is defined as he net positive charge experienced by an electron in an atom. It is termed "effective" because the shielding effect of electrons prevents higher orbital electrons from experiencing the full nuclear charge of the nucleus due to the repelling effect of inner-layer electrons.

The 1s is the closest shell to the nucleus of an therefore maximum nuclear charge is experienced. The formula for effective nuclear charge is:

Zeff = Z – S

where

Z = the number of protons in the nucleus, and

S = the shielding constant, the average number of electrons between the nucleus and the electron.

Hence, the energy required to remove an electron from the 1s orbital is the strongest.

3 0
4 years ago
Traditional Indonesian music uses an ensemble called a gamelan that is based on tuned percussion instruments somewhat like gongs
Vlada [557]

Answer:

n = 10 beats

Explanation:

Given:

- Frequency of note f1 = 151 Hz

- Frequency of note f2 = 155 Hz

- The total time they ring t = 2.5 s

Find:

How many beats are heard

Solution:

- The frequency of beat (fb) is the difference between the two frequencies of notes as follows:

                                fb = f2 - f1

                                fb = 155 - 151

                                fb = 4 Hz

- The number of beats per second is also called beat frequency:

                                n = fb*t

                                n = 4*2.5

                                n = 10 beats

           

3 0
4 years ago
A solid of density 8000 kgm.. weighs 0.8 kgf in air. When it is completely
ad-work [718]

Answer:<em> 0.5kg</em>

Explanation:

5 0
3 years ago
A simple pendulum is used to determine the acceleration due to gravity at the surface of a planet. The pendulum has a length of
Dafna1 [17]

Answer:

<em>-</em><em> </em><em>p</em><em>e</em><em>n</em><em>d</em><em>u</em><em>l</em><em>u</em><em>m</em><em> </em><em>u</em><em>s</em><em>e</em><em> </em><em>t</em><em>o</em><em> </em><em>d</em><em>e</em><em>t</em><em>e</em><em>r</em><em>m</em><em>i</em><em>n</em><em>e</em><em> </em><em>a</em><em>c</em><em>c</em><em>e</em><em>l</em><em>e</em><em>r</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em>

Explanation:

<u>b</u><u>y</u><u> </u><u>c</u><u>a</u><u>l</u><u>c</u><u>u</u><u>l</u><u>a</u><u>t</u><u>i</u><u>n</u><u>g</u><u> </u><u>n</u><u>e</u><u>e</u><u>d</u><u> </u><u>t</u><u>o</u><u> </u><u>u</u><u>n</u><u>d</u><u>e</u><u>r</u><u>s</u><u>t</u><u>a</u><u>n</u><u>d</u><u> </u><u>f</u><u>i</u><u>r</u><u>s</u><u>t</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>p</u><u>r</u><u>o</u><u>b</u><u>l</u><u>e</u><u>m</u>

<em>t</em><em>h</em><em>e</em><em> </em><em>l</em><em>e</em><em>n</em><em>g</em><em>t</em><em>h</em><em> </em><em>i</em><em>s</em><em> </em><em>m</em><em>e</em><em>a</em><em>s</em><em>u</em><em>r</em><em>e</em><em> </em><em>t</em><em>o</em><em> </em><em>b</em><em>e</em><em> </em><em>2</em><em>s</em>

<em>t</em><em>h</em><em>e</em><em> </em><em>l</em><em>e</em><em>n</em><em>g</em><em>h</em><em>t</em><em> </em><em>i</em><em>s</em><em> </em><em>a</em><em>l</em><em>s</em><em>o</em><em> </em><em>2</em>

<em>2</em><em> </em><em>o</em><em>b</em><em>t</em><em>a</em><em>i</em><em>n</em><em>e</em><em>r</em><em> </em><em>o</em><em>n</em><em> </em><em>i</em><em>n</em><em>v</em><em>i</em><em>s</em><em>t</em><em>i</em><em>g</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>m</em><em>o</em><em>s</em><em>t</em><em> </em><em>n</em><em>e</em><em>a</em><em>r</em><em>l</em><em>y</em><em> </em><em>i</em><em>s</em><em> </em><em>8</em><em>.</em>

5 0
3 years ago
A soccer ball is kicked from the ground with an initial speed v at an upward angle θ. A player a distance d away in the directio
Nady [450]

Answer:

The speed of player is given by

V=\frac{2v^{2} 2sin\alpha.cos\alpha-gd }{2vsin\alpha}

Explanation:

The time of flight for a projectile motion is given by

T=\frac{2vsin\alpha }{g}    (i)

where t is the time of flight, v is the initial speed, and α is the angle.

Now the person must also reach the impact point of ball in the same time as above.

Now the total distance D the player needs to cover is basically R horizontal range of projectile minus the distance d, range R is given by,

R=\frac{2v^{2} sin2\alpha }{g}

Now the distance the player must cover is given by

D= R-d

D= \frac{2v^{2} sin2\alpha }{g}  - d

 

D=\frac{2v^{2}sin2\alpha-gd}{g}  (ii)

Now the average speed of player is given by

V=\frac{D}{T}   (iii)

Replacing the values of D and T from eq. (i) and (ii) in eq. (iii).

V=\frac{\frac{2v^{2} sin2\alpha-gd }{g}}{\frac{2vsin\alpha }{g} }

V=\frac{2v^{2} 2sin\alpha.cos\alpha-gd }{2vsin\alpha}

3 0
3 years ago
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