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yKpoI14uk [10]
3 years ago
7

What do miles, kilometers, and light-years have in common?​

Physics
1 answer:
Radda [10]3 years ago
6 0

They are all units of measure of length

Explanation:

Length is a scalar quantity representing a distance between two points, and it can be expressed in different units.

The SI units of the length is the metre (m), which is defined as the length of the path travelled by light in vacuum during a time interval of 1/299,792,458 of a second.

A unit which is common used is a multiple of the meter, the kilometre (km) which corresponds to 1000 metres:

1 km = 1000 m

Another unit used in the UK system is the mile (mi), where the conversion factor between miles and metres is

1 mi = 1609.34 m

Finally, these units are not suitable to be used to measure astronomical distances - such as those between stars and galaxies. For this, another unit is used, which is the light-year (ly), which corresponds to the distance travelled by the light in a vacuum in one year, and its conversion factor to the metre is:

1 ly = 9.46\cdot 10^{15}ly

Learn more about distance here:

brainly.com/question/3969582

#LearnwithBrainly

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An egg falls out of a nest of a tree. It freefalls for 1.5 seconds, and then hits the ground. From how high up did the egg fall?
Alika [10]

Answer:

11.025m

Explanation:

Using kinematics,

u = Initial velocity = 0.

t = Time taken = 1.5sec.

a = Acceleration from gravity = 9.8m/s^2

Distance = s

= ut + 1/2 * a * t^2

= 0 + 1/2 * 9.8 * (1.5)^2

= 11.025m

3 0
3 years ago
Read 2 more answers
A heat pump is used to maintain a house at 22°C by extracting heat from the outside air on a day when the outside air temperatur
Ilia_Sergeevich [38]

Answer:

It is enough

Explanation:

To develop the problem it is necessary to take into account the concepts related to the coefficient of performance of a pump.

The two ways in which the performance coefficient can be expressed are given by:

COP_p = \frac{T_H}{T_H-T_L}

Where,

T_H =High Temperature

T_L = Low Temperature

And the other way is,

COP_p = \frac{\dot{Q}}{W}

Where \dot{Q} is heat rate and W the power consumed.

We have all our terms in Celsius, so we calculate the temperature in Kelvin

T_H = 22+273 = 295K

T_L = 2+273 = 275k

The rate at which heat is lost is:

\dot{Q} = 110000kJ/h

The power consumed by the heat pump is

\dot{W} = 5kW

And the coefficient of performance is

COP_p = \frac{T_H}{T_H-T_L}

COP_p = \frac{295}{295-275}

COP_p = 14.75

With this value we can calculate the Power required,

COP_p = \frac{\dot{Q}}{W}

14.75 = \frac{110000}{W}

W = \frac{110000}{3600*14.75}

W = 2.07kW

<em>The power consumed is consumed is 5kW which is more than 2.07kW so this heat pump powerful enough.</em>

4 0
3 years ago
A projectile is fired into the air at a 35o angle to the horizontal and an initial velocity of 120 m/s. what are the x and y com
Anarel [89]

Answer:

See below

Explanation:

X component = 120 * cos 35° =  98.298 m/s

Y component = 120 * sin 35° = 68.829 m/s

4 0
2 years ago
If the speed of a motor scooter doubles, which of the following also doubles? 1)kinetic energy 2) acceleration 3) momentum 4) al
emmasim [6.3K]

Answer:

3

Explanation:

-The formula for kinetic energy is the following:

K.E.=\frac{1}{2}mv^{2}

where:

K.E. is kinetic energy

m is mass

v is velocity

Here we can see that kinetic energy is proportional to the velocity squared, so if the speed or velocity of the scooter doubles then this would quadruple its kinetic energy.

-The acceleration is the rate of change of velocity per unit of time. A scooter could double its speed with a constant acceleration, so an increase in speed doesn't necessarily mean an increase in acceleration.

-The formula for momentum is the following:

p=mv

where:

p is momentum

m is the mass of the object

v is the objects velocity

Here we can see that the momentum is directly proportional to the velocity, so if the scooter where to double its velocity then it would also double its momentum.

6 0
4 years ago
PLEASE HELP ASAPP!!!
Sati [7]

Answer:

hello

Explanation:

for average speed the total distance is important so.

and you must convert min to hour 15 min is 1/4 or 0.25 hour

s =  \frac{x}{t}  =  \frac{12}{0.25}  = 48 \frac{km}{h}

for average velocity the straight line distance is important so

v =  \frac{d}{t}  =  \frac{8}{0.25}  = 32 \frac{km}{h}

hope you understand

7 0
2 years ago
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