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yKpoI14uk [10]
3 years ago
7

What do miles, kilometers, and light-years have in common?​

Physics
1 answer:
Radda [10]3 years ago
6 0

They are all units of measure of length

Explanation:

Length is a scalar quantity representing a distance between two points, and it can be expressed in different units.

The SI units of the length is the metre (m), which is defined as the length of the path travelled by light in vacuum during a time interval of 1/299,792,458 of a second.

A unit which is common used is a multiple of the meter, the kilometre (km) which corresponds to 1000 metres:

1 km = 1000 m

Another unit used in the UK system is the mile (mi), where the conversion factor between miles and metres is

1 mi = 1609.34 m

Finally, these units are not suitable to be used to measure astronomical distances - such as those between stars and galaxies. For this, another unit is used, which is the light-year (ly), which corresponds to the distance travelled by the light in a vacuum in one year, and its conversion factor to the metre is:

1 ly = 9.46\cdot 10^{15}ly

Learn more about distance here:

brainly.com/question/3969582

#LearnwithBrainly

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MAXImum [283]
By Newton's 2nd law, m*a=sum_of_forces where m is the mass and a the acceleration. Here there are two forces in opposed directions.

Thus 5*a=40-8=32 therefore a=32/5=6.4m^s/2
7 0
3 years ago
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Calculate the potential V(r) for r>rb. (Hint: The net potential is the sum of the potentials due to the individual spheres.)
Marat540 [252]

Answer:

The potential for r > rb is equal to zero.

Explanation:

For r > rb, the potential is:

V=\frac{Kq}{r}

Then, the net potential is:

V_{(r)} =\frac{K(+\epsilon )}{r} +\frac{K(-\epsilon )}{r}

K=\frac{1}{4\pi \epsilon _{o}  }

V_{(r)} =\frac{K(+\epsilon )}{r} -\frac{K(\epsilon )}{r}\\V_{(r)}=0

8 0
4 years ago
"An alpha particle (He2+) with a velocity of 2.6x106m/scrosses a uniform magnetic field at an angle of 37.0°to the field lines a
sergey [27]

Answer:

B = 5.59x10⁹ T

Explanation:

The magnetic force (F), on a the alpha particle with charge (q) that is moving at velocity (v) as the cross product of the velocity and magnetic field (B) is:

F = qvBsin(\theta)

<u>We have:</u>

F = 1.4x10⁻³ N

v = 2.6x10⁶ m/s

θ = 37.0°

q = 2*p = 2*1.6x10⁻¹⁹ C

Hence, the strength of the magnetic field is:

B = \frac{F}{qvsin(\theta)} = \frac{1.4 \cdot 10^{-3}}{1.6 \cdot 10^{-19} C*2.6 \cdot 10^{6}*sin(37)} = 5.59 \cdot 10^{9} T

Therefore, the strength of the magnetic field is 5.59x10⁹ T.

I hope it helps you!

7 0
3 years ago
If the flea jumps straight up, how high will it go? (Ignore air resistance for this problem; in reality, air resistance plays a
Savatey [412]

Answer:

The flea will reach to a height of 5.2 cm.

Explanation:

Let us assume it is given that, a flea reaches a takeoff speed of 1.0 m/s over a distance of 0.50 mm.

Initial speed, u = 1 m/s

Initial distance, x = 0.5 mm

We need to find the height reached by the flea. Using third equation of motion to find it.

At maximum height, its final speed, v = 0

v^2-u^2=2ah

Here, a = -g

-u^2=-2g(h-x)\\\\1^2=2\times 9.8\times (h-0.5\times 10^{-3})\\\\h=0.052\ m

or

h = 5.2 cm

So, the flea will reach to a height of 5.2 cm.

6 0
3 years ago
Trên bóng đèn có ghi là 12v -6w. Khi đèn sáng bình thường thì dòng điện chạy qua đèn có cường độ là
mrs_skeptik [129]

Answer:

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Explanation: P=UI ( CÔNG SUẤT = HIỆU ĐIỆN THẾ NHÂN VỚI C Đ D Đ)

4 0
3 years ago
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