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Flura [38]
3 years ago
7

The _______ is the coldest layer of the atmosphere

Physics
1 answer:
n200080 [17]3 years ago
4 0
The mesosphere is the coldest layer of the atmosphere. It is located above the stratosphere. 
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A solid cylinder with a radius of 10 cm and a mass of 3.0 kg is rotating about its center with anangular speed of 3.5 rad/s. Wha
Lynna [10]

Answer:

kE=0.0735 J

Explanation:

Given that

Radius ,R=10 cm = 0.1 m

Mass ,m= 3 kg

Angular speed ,ω = 3.5 rad/s

We know that moment of inertia for solid sphere given as

I=\dfrac{2}{5}mR^2

Kinetic energy

KE=\dfrac{1}{2}I\omega^2

Now by putting the values

KE=\dfrac{1}{2}\times \dfrac{2}{5}mR^2\times \omega^2

KE=\dfrac{1}{2}\times \dfrac{2}{5}\times 3\times 0.1^2\times 3.5^2\ J

kE=0.0735 J

Therefore the kinetic energy will be 0.0735 J

3 0
3 years ago
A ball falls off the desk and hits the floor. Which
Yuliya22 [10]

Answer:

The potential energy is transformed into kinetic energy

Explanation:

This particular case is defined as the principle of energy conservation since energy is not created or destroyed only transforms. When you have potential energy it can be transformed into kinetic energy or vice versa. In this problem, we have the case of a ball that sits on a desk and then falls to the ground. In this way the ground will be taken as a reference point, this is a point at which the potential energy will be equal to zero in such a way that when the ball is on the desktop that is above the reference line its potential energy will be maximum. As the ball drops its potential energy decreases, as the height relative to the ground (reference point) decreases. In contrast its kinetic energy increases and increases as it approaches the ground. So when it hits the ground it will have maximum kinetic energy and will be equal to the potential energy for when the ball was on the desk.

Therefore:

E_{p} = potential energy [J] = E_{k} = kinetic energy [J]where:\\E_{p} =m*g*h\\m =mass [kg]\\g=gravity[m/s^2]\\h=elevation[m]\\E_{k} = \frac{1}{2} *m*v^{2} \\where:\\v=velocity [m/s]\\\frac{1}{2}  *m*v^{2} = m*g*h

8 0
3 years ago
What is the minimum angular spread (in rad) of a 534 nm wavelength manganese vapor laser beam that is originally 1.19 mm in diam
Ad libitum [116K]

Answer:

Minimum angular spread (in rad) = 547.45 x 10⁻⁶ rad

Explanation:

GIven;

Wavelength of manganese vapor laser beam = 534 nm = 534 x 10⁻⁹ m

Diameter =  1.19 mm = 1.19 x 10⁻³ m

Find:

Minimum angular spread (in rad)

Computation:

Minimum angular spread (in rad) = 1.22[Wavelength / Diameter]

Minimum angular spread (in rad) = 1.222[(534 x 10⁻⁹) / (1.19 x 10⁻³)]

Minimum angular spread (in rad) = 2[448.73 x 10⁻⁶]

Minimum angular spread (in rad) = 547.45 x 10⁻⁶ rad

6 0
3 years ago
The terminal velocity of a sand grain in air is __________ the terminal velocity of the same sand grain in seawater. greater tha
hoa [83]
<span>The terminal velocity of a sand grain in the air is greater than the terminal velocity of the same sand grain in seawater. The terminal velocity is greater in the air because it is less dense compared to a much denser sea water. Terminal velocity takes lace when an object is constantly free-falling.</span>
7 0
4 years ago
49 POINTS!!!
Sladkaya [172]

Answer:

Explanation:

chemical kinetic

electric potenitial

Electromagnetic (light, x Ray's, microwaves, etc) kinetic

Gravitational potential

heat kinetic

Movement of mass kentic

8 0
3 years ago
Read 2 more answers
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