Answer:
kE=0.0735 J
Explanation:
Given that
Radius ,R=10 cm = 0.1 m
Mass ,m= 3 kg
Angular speed ,ω = 3.5 rad/s
We know that moment of inertia for solid sphere given as

Kinetic energy

Now by putting the values


kE=0.0735 J
Therefore the kinetic energy will be 0.0735 J
Answer:
The potential energy is transformed into kinetic energy
Explanation:
This particular case is defined as the principle of energy conservation since energy is not created or destroyed only transforms. When you have potential energy it can be transformed into kinetic energy or vice versa. In this problem, we have the case of a ball that sits on a desk and then falls to the ground. In this way the ground will be taken as a reference point, this is a point at which the potential energy will be equal to zero in such a way that when the ball is on the desktop that is above the reference line its potential energy will be maximum. As the ball drops its potential energy decreases, as the height relative to the ground (reference point) decreases. In contrast its kinetic energy increases and increases as it approaches the ground. So when it hits the ground it will have maximum kinetic energy and will be equal to the potential energy for when the ball was on the desk.
Therefore:
![E_{p} = potential energy [J] = E_{k} = kinetic energy [J]where:\\E_{p} =m*g*h\\m =mass [kg]\\g=gravity[m/s^2]\\h=elevation[m]\\E_{k} = \frac{1}{2} *m*v^{2} \\where:\\v=velocity [m/s]\\\frac{1}{2} *m*v^{2} = m*g*h](https://tex.z-dn.net/?f=E_%7Bp%7D%20%3D%20potential%20energy%20%5BJ%5D%20%3D%20E_%7Bk%7D%20%3D%20kinetic%20energy%20%5BJ%5Dwhere%3A%5C%5CE_%7Bp%7D%20%3Dm%2Ag%2Ah%5C%5Cm%20%3Dmass%20%5Bkg%5D%5C%5Cg%3Dgravity%5Bm%2Fs%5E2%5D%5C%5Ch%3Delevation%5Bm%5D%5C%5CE_%7Bk%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2Am%2Av%5E%7B2%7D%20%5C%5Cwhere%3A%5C%5Cv%3Dvelocity%20%5Bm%2Fs%5D%5C%5C%5Cfrac%7B1%7D%7B2%7D%20%20%2Am%2Av%5E%7B2%7D%20%3D%20m%2Ag%2Ah)
Answer:
Minimum angular spread (in rad) = 547.45 x 10⁻⁶ rad
Explanation:
GIven;
Wavelength of manganese vapor laser beam = 534 nm = 534 x 10⁻⁹ m
Diameter = 1.19 mm = 1.19 x 10⁻³ m
Find:
Minimum angular spread (in rad)
Computation:
Minimum angular spread (in rad) = 1.22[Wavelength / Diameter]
Minimum angular spread (in rad) = 1.222[(534 x 10⁻⁹) / (1.19 x 10⁻³)]
Minimum angular spread (in rad) = 2[448.73 x 10⁻⁶]
Minimum angular spread (in rad) = 547.45 x 10⁻⁶ rad
<span>The terminal velocity of a sand grain in the air is greater than the terminal velocity of the same sand grain in seawater. The terminal velocity is greater in the air because it is less dense compared to a much denser sea water. Terminal velocity takes lace when an object is constantly free-falling.</span>
Answer:
Explanation:
chemical kinetic
electric potenitial
Electromagnetic (light, x Ray's, microwaves, etc) kinetic
Gravitational potential
heat kinetic
Movement of mass kentic