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3 years ago

500 at 6% for 2 years what's the monthly payment

Mathematics

2 answers:

arsen [322]3 years ago

8 0

Answer: the simplest form would be 200 but thats it srry man

Step-by-step explanation:

Savatey [412]3 years ago

6 0

Answer:

The answer is 200

Step-by-step explanation:

You might be interested in

Divide. Give the quotient and the remainder<br> 1493/6

mrs_skeptik [129]

Answer:

248 with remainder 5

Step-by-step explanation:

thats it

6 0

2 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

3 years ago

Solve for x: 2(x-3)+5=4-7(2x-1)

Marat540 [252]

Solve for x by simplifying both sides of the equation , then isolating the variable
your answer is x=3/4

3 0

2 years ago

Can someone help me? And possibley tell me how to solve this as well? I'm totally clueless haha

Bumek [7]

Answer:

? = 3

Step-by-step explanation:

To find the value of ?, substitute one of the ordered pairs from the table [except (0, 0)] into the given formula and solve for ?.

Given formula:

$\sf y=\boxed{?} \:x$

Substitute x = 1 and y = 3 into the formula:

$\sf 3=\boxed{?} \:1$

To isolate ? divide both sides by 1:

$\implies \sf \dfrac{3}{1}=\dfrac{\boxed{?} \:1}{1}$

$\implies \sf 3=\boxed{?}$

Therefore, ? = 3:

$\implies \sf y=3x$

Check by inputting another value of x from the table into the found formula and comparing the calculated y-value:

$\sf x=-2 \implies y=3(-2)=-6 \quad \boxed{\sf correct}$

$\sf x=3 \implies y=3(3)=9 \quad \boxed{\sf correct}$

5 0

1 year ago

Read 2 more answers

How to solve -2y-4=4(y-1)

tangare [24]

-2y-4=4(y-1)

Always remove the pararentheses as your first step.

-2y-4 = 4y - 4

Combine like terms.

-2y - 4y = 4 - 4

-6y = 0

Divide both sides by -6 to find y.

-6y/-6 = 0/-6

y = 0

Done

6 0

3 years ago

Read 2 more answers