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sdas [7]
3 years ago
12

Knife or rope its a science question.

Mathematics
2 answers:
Agata [3.3K]3 years ago
6 0

Answer:

knife or rope for what tho?

Step-by-step explanation:

anyways whatever it is I go for the knife

gogolik [260]3 years ago
5 0

Answer:

it depends on the situation

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Please help need answer for both questions
myrzilka [38]

Answer:

1. 32, 12

2. Enlargement

Step-by-step explanation:

Enlarged by a scale factor of 4

(Multiply all points by 4)

8 x 4 = 32

3 x 4 = 12

It is an enlargement because the points are larger than before.

5 0
3 years ago
In the diagram below, we have ST parallel to QR. angle P= 40 degrees, and angle Q= 35 degrees. Find the measure of angles STR in
Drupady [299]

Answer:

m\angle S = 35^\circ, \ m\angle T = 105^\circ,\ m\angle R = 105^\circ

Step-by-step explanation:

<u>Similar Triangles</u>

Lines ST and QR are parallel. Thus, angles S and Q are congruent, and angles T and R are congruent.

Considering the triangle PQR, the sum of its internal angles must be 180°:

m\angle P + m\angle Q + m\angle R = 180^\circ

Substituting the known values:

40^\circ + 35^\circ + m\angle R = 180^\circ

Solving for R:

m\angle R = 180^\circ - 40^\circ - 35^\circ

m\angle R = 105^\circ

Angles S and Q are congruent, thus

m\angle S = 35^\circ

Angles T and R are congruent, thus

m\angle T = 105^\circ

Summarizing:

\mathbf{m\angle S = 35^\circ, \ m\angle T = 105^\circ,\ m\angle R = 105^\circ}

7 0
3 years ago
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What are the solutions to 3n-1&gt;8 or 4n+3 &lt; -1? *​
hammer [34]

Answer:

3’d

Step-by-step explanation:

6 0
3 years ago
A rocket is launched at 85 ft./s from a launch pad that’s 28 feet above the ground. which equation can be used to determine the
3241004551 [841]

Answer:

h(t)=-16t^2+85t+28  is equation of height of rocket.

Option D is correct.

Step-by-step explanation:

Given: A rocket is launched with speed 85 ft/s from a height 28  feet.

Launching a rocket follows the path of parabola. The equation of rocket should be parabolic.

Parabolic equation of rocket is

Formula: h(t)=\dfrac{1}2gt^2+v_0t+h_0

g ⇒ acceleration due to gravity (-32 ft/s)

v ⇒ Initial velocity (v_0=85\ ft/s)

h ⇒ Initial height (h_0=28\ feet)

h(t) ⇒ function of height at any time t

Substitute the given values into formula

h(t)=\frac{1}{2}(-32)t^2+(85)t+28

h(t)=-16t^2+85t+28

D is correct.

6 0
4 years ago
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alexandr402 [8]
The answer is zero there is no slope

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