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2 years ago

What is the area???

Mathematics

1 answer:

Natalka [10]2 years ago

4 0

Answer:

in squared 252

Step-by-step explanation: idk how but

9 times 12= 108

6 times 15=90

6 times 9=54

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Rhys will tile the rectangle below to find it’s area. Q: How many unit squares with side length 1/10 foot will Rhys use to tile

Inessa [10]

The number of unit squares with a side length of 1/10 foot that Rhys uses to tile the rectangle is 24 units

<h3>How to calculate the area of plane shapes?</h3>

A square is a plane shape with 4 sides

The formula for calculating the area of the square is expressed as:

A = l^2

Given

side length of a square = 1/10 foot

A = (1/10)² = 1/100 = 0.01 square foot

<u>Determine the area of the rectangle</u>

Area = length * width

Area = 3/10 * 4/5
Area = 12/50 = 6/25
Area = 0.24 square foot

<u>Take the ratio of both areas</u>

Ratio = 0.24/0.01

Ratio = 24 units

Hence the number of unit squares with a side length of 1/10 foot that Rhys uses to tile the rectangle is 24 units

Learn more on area of plane shapes here: brainly.com/question/2644832

7 0

2 years ago

Read 2 more answers

Brainliest to who ever answers first.

JulsSmile [24]

2x10^-10
1x10^-10
8x10^-11
7x10^-11

3 0

3 years ago

What is the area of a square with a length of 5

wlad13 [49]

Answer:

Step-by-step explanation:

3 0

3 years ago

The radius of a sphere is measured as 7 centimeters, with a possible error of 0.025 centimeter.

lord [1]

Answer:

a) dV(s) = 15,386 cm³

b) dS(s) = 4,396 cm²

c) dV(s)/V(s) = 1,07 % and dS(s)/ S(s) = 0,71 %

Step-by-step explanation:

a) The volume of the sphere is

V(s) = (4/3)*π*x³ where x is the radius

Taking derivatives on both sides of the equation we get:

dV(s)/ dr = 4*π*x² or

dV(s) = 4*π*x² *dr

the possible propagated error in cm³ in computing the volume of the sphere is:

dV(s) = 4*3,14*(7)²*(0,025)

dV(s) = 15,386 cm³

b) Surface area of the sphere is:

V(s) = (4/3)*π*x³

dV(s) /dx = S(s) = 4*π*x³

And

dS(s) /dx = 8*π*x

dS(s) = 8*π*x*dx

dS(s) = 8*3,14*7*(0,025)

dS(s) = 4,396 cm²

c) The approximates errors in a and b are:

V(s) = (4/3)*π*x³ then

V(s) = (4/3)*3,14*(7)³

V(s) = 1436,03 cm³

And the possible propagated error in volume is from a) is

dV(s) = 15,386 cm³

dV(s)/V(s) = [15,386 cm³/1436,03 cm³]* 100

dV(s)/V(s) = 1,07 %

And for case b)

dS(s) = 4,396 cm²

And the surface area of the sphere is:

S(s) = 4*π*x³ ⇒ S(s) = 4*3,14*(7)² ⇒ S(s) = 615,44 cm²

dS(s) = 4,396 cm²

dS(s)/ S(s) = [ 4,396 cm²/615,44 cm² ] * 100

dS(s)/ S(s) = 0,71

8 0

3 years ago

Anyone know the answer

Nat2105 [25]

Hello there,

So what we need to find how many number of costumes that can be made using ONLY 11 $\frac{1}{4}$ .

The first thing we would do is $\frac{3}{4}$ ÷11 $\frac{1}{4}$ .

Your answer this this would be $\frac{1}{15}$ .

To recheck this. . . We do $\frac{1}{15}$ x $\frac{3}{4}$ . . .

Your answer would be 11 $\frac{1}{4}$ .

That is how you recheck your work.

Your correct answer would be $\frac{1}{15}$

Hope this helps! :)

7 0

3 years ago

Read 2 more answers