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Nataliya [291]
3 years ago
5

Three weeks ago John bought stock at 49 1/4; today the stock is valued at 49 7/8. We could say the stock is performing at which

of the following?
A. Below par
B. Par equality
C. On par
D. Above par
Mathematics
2 answers:
Bad White [126]3 years ago
7 0

Answer:

The correct option is D.

Step-by-step explanation:

John bought stock at 49\frac{1}{4}; today the stock is valued at 49\frac{7}{8}.

49\frac{1}{4}=49+\frac{1}{4}

49\frac{1}{4}=49+0.25

49\frac{1}{4}=49.25

The value of stock at the time of purchasing is 49.25.

49\frac{7}{8}=49+\frac{7}{8}

49\frac{7}{8}=49+0.875

49\frac{7}{8}=49.875

The value of stock at current time is 49.875.

49.875-49.25=0.625

The value of stock increased by 0.625.

Since the value of stock increases, therefore the correct option is D, i.e., Above par.

Elanso [62]3 years ago
6 0
The best answer to the question that is being presented above would be letter D above par. The stock is performing at above par because there is an increase in the value of the stock by twenty nine percent (29%). 
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Answer:

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3 0
3 years ago
Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes
azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

  • The centre of the ellipse is at the origin and the X axis is the major axis

  • It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

  • The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

Given that the ellipse passes through the point (-3, 1)

Hence,

\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1

Cross multiplying we get,

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Multiply by 4 on both sides,

  • 4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1

Cross multiply,

  • 4b² + 4a² = 1 × a²b²
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Subtracting equations 2 and 1,

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Substituting in 2,

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Substituting the values in the equation for ellipse,

\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1

\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
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Answer:

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Step-by-step explanation:

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Answer:

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4 0
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