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antiseptic1488 [7]
3 years ago
14

Simplify fully 4x^2+4x/2x^2-2

Mathematics
1 answer:
prisoha [69]3 years ago
3 0

Answ

Step-by-step explanation:

2x^3+4x^2-2

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- Polynomial Functions -For each function, state the vertex; whether the vertex is a maximum or minimum point; the equation of t
vladimir2022 [97]

EXPLANATION

Given the function f(x) = (x-6)^2 + 1

\mathrm{The\: vertex\: of\: an\: up-down\: facing\: parabola\: of\: the\: form}\: y=ax^2+bx+c\: \mathrm{is}\: x_v=-\frac{b}{2a}

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

=x^2-12x+37\mathrm{The\: parabola\: params\: are\colon}a=1,\: b=-12,\: c=37x_v=-\frac{b}{2a}x_v=-\frac{\left(-12\right)}{2\cdot\:1}\mathrm{Simplify}x_v=6y_v=6^2-12\cdot\: 6+37

Simplify:

y_v=1

\mathrm{Therefore\: the\: parabola\: vertex\: is}\mleft(6,\: 1\mright)\mathrm{If}\: a\mathrm{If}\: a>0,\: \mathrm{then\: the\: vertex\: is\: a\: minimum\: value}a=1\mathrm{Minimum}\mleft(6,\: 1\mright)\mathrm{For\: a\: parabola\: in\: standard\: form}\: y=ax^2+bx+c\: \mathrm{the\: axis\: of\: symmetry\: is\: the\: vertical\: line\: that\: goes\: through\: the\: vertex}\: x=\frac{-b}{2a}

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

y=x^2-12x+37\mathrm{Axis\: of\: Symmetry\: for}\: y=ax^2+bx+c\: \mathrm{is}\: x=\frac{-b}{2a}a=1,\: b=-12x=\frac{-\left(-12\right)}{2\cdot\:1}\mathrm{Refine}

Axis of simmetry : x=6

The quadratic function has the same shape than the parent function y=x^2 because there is NOT a coefficient within x.

3 0
1 year ago
If all four sides of an quadrilateral measure the same length, and one corner angle measures 90 degrees, circle the shape that t
son4ous [18]

Answer:

All of the above

Step-by-step explanation:

ALL of the above quadrilaterals have all these characteristics.

7 0
4 years ago
Help don't answer if you don't know!!!!
MAXImum [283]

Answer:

48

Step-by-step explanation:

Since it's a right angle, it's automadically 90 degrees so you just have to add 23+ 19 and subtract from 90.

23 + 19 = 42

90 - 42 = 48

4 0
3 years ago
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