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2 years ago

I need help klcan you draw it , thanks

Mathematics

1 answer:

NARA [144]2 years ago

8 0

Answer:

Step-by-step explanation:

I think it may look like this?

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Find the value of the variables. x and y

Dmitriy789 [7]

Answer:

x = 29.4

y = 17

Step-by-step explanation:

sin 90° / 34 = sin 60° / x

x = 34·sin 60°

x = 29.4

sin 90° / 34 = sin 30° / y

y = 34·sin 30°

y = 17

8 0

3 years ago

Which equation is true about the measure of the angles of the triangle?the measure of angle prq is equal to 100 degreesthe measu

harkovskaia [24]

I believe this question is missing an image. However, I will just tell how how to solve such question and you can apply this solution to the triangle you have.

In any given triangle, the sum of the measure of the three angles must be equal to 180 degrees.
Therefore, for a triangle pqr:
measure angle pqr + measure angle prq + measure angle rqp = 180 degrees

If you have one angle given, then the sum of the other two angles will be equal to 180 - measure of the given angle.

If you have two angles given, then the measure of the third angle will be equal to 180 - the sum of the other two angles.

3 0

3 years ago

What is the constant in this expression<br> 4+8m+x

Strike441 [17]

4 is the contestant in the expression

5 0

3 years ago

Use a power series to approximate the value of the integral with an error of less than 0.0001. (Round your answer to four decima

otez555 [7]

Answer:

The answer is "0.9461"

Step-by-step explanation:

Given:

$\int^1_0 \frac{sin(x)}{x} dx\\\\$

$\int^1_0 \frac{sin(x)}{x} dx\\\\$ ≈ $\sum^2_{n=0}\frac{(-1)^n x^{2n+1} (-1)^n (x-1)^n}{(2n + 1)!}$

$\therefore$

$\to \sin x = \sum^{\infty}_{n=0} (-1)^n\frac{x^{(2n+1)}}{(2n + 1)!}$

$\because \\\\ \to \frac{\sin x}{x} =\sum^{\infty}_{n=0} (-1)^n \frac{x^{2n+1-1}}{(2n+1)!}\\$

$=\sum^{\infty}_{n=0} (-1)^n \frac{x^{2n}}{(2n+1)!}$

The value is in between 0 and 1 then:

$\to \int^1_0 \frac{sin(x)}{x} = =\sum^{2}_{n=0} \frac{(-1)^n}{ (2n+1) (2n+1)!}$

The above-given series is an alternative series, and it will give an error, when the nth term is bounded by its absolute value, that can be described as follows:

$\to \frac{1}{(2n+3) (2n+3)!}< 0.0001\\\\\to (2n+3) (2n+3)!> 0.0001\\\\\to n\geq 2 \\$

So,

$\int^1_0 \frac{sin(x)}{x} dx\\\\$ ≈ $1 - \frac{1}{3 \cdot 3!}+\frac{1}{5 \cdot 5!}\\\\$

$\approx 1 - \frac{1}{3 \cdot 6}+\frac{1}{5 \cdot 120}\\\\\approx 1 - \frac{1}{18}+\frac{1}{600}\\\\\approx 1 - \frac{1}{18}+\frac{1}{600}\\\\\approx \frac{18-1}{18}+\frac{1}{600}\\\\\approx \frac{17}{18}+\frac{1}{600}\\\\\approx \frac{1700+3}{1800}\\\\ \approx \frac{1703}{1800}\\\\\approx 0.9461$

5 0

3 years ago

What is e area of the trapezoid?

Korvikt [17]

Answer:

Step-by-step explanation:

5out

3 0

4 years ago

I need help klcan you draw it , thanks​

I need help klcan you draw it , thanks