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Igoryamba
2 years ago
6

I need help klcan you draw it , thanks​

Mathematics
1 answer:
NARA [144]2 years ago
8 0

Answer:

Step-by-step explanation:

I think it may look like this?

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In ΔIJK, the measure of ∠K=90°, KJ = 65, IK = 72, and JI = 97. What is the value of the cosine of ∠J to the nearest hundredth?
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Answer:

\cos(J) = 0.67

Step-by-step explanation:

Given

\angle K = 90^o

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Required

\cos(J)

The question is illustrated with the attached image.

From the image, we have:

\cos(J) = \frac{KJ}{JI}

This gives:

\cos(J) = \frac{65}{97}

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