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3 years ago

Which statement is true about a right triangle?

Mathematics

2 answers:

VashaNatasha [74]3 years ago

5 0

Its A because all angles must equal 180 degrees

Nesterboy [21]3 years ago

5 0

The answer is A because if it is a 45-45-90 right triangle then all angles other than the right angle (one with the box) must be 45 and 45. 45 +45= 90. 90+90= 180.

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PLEASE HELP ME!!!!!!!!!

Ray Of Light [21]

1. perpendicular is the exact opposite. So, it would be -1/4, which is A.

2. Sorry, cant help you :(

3. y = -3x - 4 (A)

Hope tis helps!!
~Kiwi

7 0

3 years ago

12.8 rounded to the nearest whole number

Lyrx [107]

Answer:

Step-by-step explanation:

you're kidding, how do you not know this but I mean I'm here to help even if you're not the brightest

6 0

3 years ago

Read 2 more answers

This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex

olga nikolaevna [1]

$f(x_1,\ldots,x_n)=x_1+\cdots+x_n=\displaystyle\sum_{i=1}^nx_i$

${x_1}^2+\cdots+{x_n}^2=\displaystyle\sum_{i=1}^n{x_i}^2=4$

The Lagrangian is

$L(x_1,\ldots,x_n,\lambda)=\displaystyle\sum_{i=1}^nx_i+\lambda\left(\sum_{i=1}^n{x_i}^2-4\right)$

with partial derivatives (all set equal to 0)

$L_{x_i}=1+2\lambda x_i=0\implies x_i=-\dfrac1{2\lambda}$

for $1\le i\le n$ , and

$L_\lambda=\displaystyle\sum_{i=1}^n{x_i}^2-4=0$

Substituting each $x_i$ into the second sum gives

$\displaystyle\sum_{i=1}^n\left(-\frac1{2\lambda}\right)^2=4\implies\dfrac n{4\lambda^2}=4\implies\lambda=\pm\frac{\sqrt n}4$

Then we get two critical points,

$x_i=-\dfrac1{2\frac{\sqrt n}4}=-\dfrac2{\sqrt n}$

$x_i=-\dfrac1{2\left(-\frac{\sqrt n}4\right)}=\dfrac2{\sqrt n}$

At these points we get a value of $f(x_1,\cdots,x_n)=\pm2\sqrt n$ , i.e. a maximum value of $2\sqrt n$ and a minimum value of $-2\sqrt n$ .

6 0

4 years ago

Can anyone please answer these for me?

yulyashka [42]

11. y=-3x-5

12. y=-5

13. y= -1/3x+5

14. y=3x-5

3 0

4 years ago

an open concrete tank is internally 1m wide, 2m long and 1.5m deep, the concrete being 10cm thick. Calculate the capacity of the

mixer [17]

Capacity of tank in litres:

1x2x1.5=3m^3 or 3000 litres

Volume of concrete:

(0.1*1.5*1*2)+(0.1*1.5*2(0.1*2))*2)+(0.1*1.2*2.2)=0.3+0.66+0.264=1.224 m^3 of concrete

(Thickness x Depth x Width excluding the thickness of the wall x Two sides) + (Thickness x Depth x Length including the thickness of the wall on both sides x Two sides) + (Base slab dimensions)

7 0

3 years ago