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crimeas [40]
3 years ago
14

Solve the linear equation

le="4^{x+7} = 8^{2x-3}" alt="4^{x+7} = 8^{2x-3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
GREYUIT [131]3 years ago
3 0

Answer:

x = 5.75

Step-by-step explanation:

4^(x+7) = 8^(2x-3)

But; 4^(x+7) = 2^2(x+7)

8^(2x-3) = 2^3(2x-3)

2^2(x+7) = 2^3(2x-3)

Since the bases are the same;

2(x+7) = 3(2x-3)

2x + 14 = 6x -9

14 + 9 = 6x - 2x

23 = 4x

x = 23/4

<u>x = 5.75</u>

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Step-by-step explanation:

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The box plot and histogram show the number of minutes sixth-grade students spent reading the previous night.Which statements bes
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I NEED HELP (I’m sooo dumb lol)
statuscvo [17]
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7 0
3 years ago
Solve for n.<br><br> n + 1 = 4(n – 8)
kolezko [41]
N + 1 = 4(n – 8)
Use distributive property for this part: 4(n – 8) ----> 4n - 32

n + 1 = 4n - 32

Get the variable on one side: 

n + 1 = 4n - 32
-n         -n

1= 3n - 32

Get the variable on its own:

1= 3n - 32 
+32       +32

33 = 3n

Divide by 3 on both sides: 

33/3 = 3n/3

n = 11



7 0
3 years ago
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