Ask question

Ask question

All categories

2 years ago

8

Rewrite this statement below to be a stronger claim. Chocolate milk is better than plain milk.

2 answers:

anyanavicka [17]2 years ago

7 0

When you take a glass of milk and stir in some luxurious liquid chocolate you have a delicous substance called chocolate milk. Plain milk is boring and has no personality whereas chocolate milk is fun, delicous, colorful. Plain milk is like so last year!

Mila [183]2 years ago

5 0

Answer:

Chocolate milk tastes better than plain milk (?)

Step-by-step explanation:

it could also be Plain milk tastes worse than Chocolate milk,

i hope these help, sorry if it doesnt :(

You might be interested in

What is 3,600 seconds per hour times 24 hours per day times 365.25 days per year?

iren2701 [21]

Answer:31557600

Step-by-step explanation:

3600 x 24 x 365.25

Which equal 31557600

8 0

2 years ago

Read 2 more answers

The answer and the work

crimeas [40]

Answer:

x=1

Step-by-step explanation:

Substitute the value of y to the first given

3x+4(-x)=-1

3x+(-4x)=-1

-x=-1

divide both sides by -1

x=1

5 0

2 years ago

4x27-3+5x2=......................

kolbaska11 [484]

Answer:

115

Step-by-step explanation:

8 0

2 years ago

Hey can you please help me posted picture of question

AnnZ [28]

I think choice a would be the correct answer. 90.

8 0

3 years ago

The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle

Vladimir [108]

Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

$|AB|=\sqrt{(-1--5)^2+(8-6)^2}$

$|AB|=\sqrt{16+4}$

$|AB|=\sqrt{20}$

The length of AD is

$|AD|=\sqrt{(-1--5)^2+(6-4)^2}$

$|AD|=\sqrt{16+4}$

$|AD|=\sqrt{20}$

The length of BC is:

$|BC|=\sqrt{(-1-3)^2+(8-6)^2}$

$|BC|=\sqrt{16+4}$

$|BC|=\sqrt{20}$

The length of CD is

$|CD|=\sqrt{(-1-3)^2+(6-4)^2}$

$|CD|=\sqrt{16+4}$

$|CD|=\sqrt{20}$

Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB $=\frac{8-6}{-1--5}=\frac{1}{2}$

Slope of BC $=\frac{8-6}{-1-3}=-\frac{1}{2}$

Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus

7 0

2 years ago

Read 2 more answers