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4 years ago

D. Write a system of two linear equations that has more than one solution.

1 answer:

3 0

D. y=5x+6 and 2y-12-10x=0 has infinitely many solutions and both lines are linear

E. y=4x+1, y=9x+4 has the solutions x = -3/5, y = -7/5

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Evaluate the following integral (Calculus 2) Please provide step by step explanation!

Step2247 [10]

Answer:

$\displaystyle \int \dfrac{2}{x^2+2x+1}\:\:\text{d}x=-\dfrac{2}{x+1}+\text{C}$

Step-by-step explanation:

Fundamental Theorem of Calculus

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given integral:

$\displaystyle \int \dfrac{2}{x^2+2x+1}\:\:\text{d}x$

Factor the denominator:

$\begin{aligned}\implies x^2+2x+1 & = x^2+x+x+1\\& = x(x+1)+1(x+1)\\& = (x+1)(x+1)\\& = (x+1)^2\end{aligned}$

$\implies \displaystyle \int \dfrac{2}{x^2+2x+1}\:\:\text{d}x=\int \dfrac{2}{(x+1)^2}\:\:\text{d}x$

$\textsf{Apply exponent rule} \quad \dfrac{1}{a^n}=a^{-n}$

$\implies \displaystyle \int \dfrac{2}{x^2+2x+1}\:\:\text{d}x=\int 2(x+1)^{-2}\:\:\text{d}x$

$\boxed{\begin{minipage}{4 cm}\underline{Integrating $ax^n$}\\\\$\displaystyle \int ax^n\:\text{d}x=\dfrac{ax^{n+1}}{n+1}+\text{C}$\end{minipage}}$

Use Integration by Substitution:

$\textsf{Let }u=(x+1) \implies \dfrac{\text{d}u}{\text{d}x}=1 \implies \text{d}x=\text{d}u}$

Therefore:

$\begin{aligned}\displaystyle \int \dfrac{2}{x^2+2x+1}\:\:\text{d}x & = \int 2(x+1)^{-2}\:\:\text{d}x\\\\& = \int 2u^{-2}\:\:\text{d}u\\\\& = \dfrac{2}{-1}u^{-2+1}+\text{C}\\\\& = -2u^{-1}+\text{C}\\\\& = -\dfrac{2}{u}+\text{C}\\\\& = -\dfrac{2}{x+1}+\text{C}\end{aligned}$

Learn more about integration here:

brainly.com/question/27988986

brainly.com/question/27805589

5 0

2 years ago

A bin contains 64 light bulbs of which 10 are defective. if 5 light bulbs are randomly selected from the bin with replacement, f

Sloan [31]

Total number of bulbs = 64
Number of defective bulbs = 10
Number of good bulbs = 64 - 10 = 54

P(5 good bulbs) = (54/64)⁵ = (27/32)⁵ = 0.428

Answer: 0.428

3 0

3 years ago

Solve: 4x-4=2(×-1)-4y+2y. show some work please:))

Papessa [141]

your answer is x = -7+1/2

7 0

3 years ago

Solve for x.

marusya05 [52]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The Venn diagram shows the number of employees who ranked skills important for their careers in the field. C

Contact [7]

Answer:

Step-by-step explanation:

In the picture attached, the Venn diagram is shown.

We can see in the picture that the intersection between C and M (symbolized by C∩M) is made by two regions, one with 22 employees and another one with 25 employees, then 22+25 = 47 satisfy C∩M

6 0

3 years ago