Answer:
100
Step-by-step explanation:
120 + 130 + 10 = 260
360 - 260 = 100
Answer:
Step-by-step explanation:
(probability of the first event) x (probability of the second event)
male community college
84/164 93/164
mutiply the two together 1953/6724 or 29%
3+9+8=20
20x1=20
That’s the answer
Answer:
the price of good x in 1999 dollars is 370.89 dollars
Step-by-step explanation:
Given that good x sold for $40 in 1945. the Cpi in 1945 was 18.0 and the cpi in 1999 was 166.6.
We have cpi and sale price have direct variation
In other words S = kC where C = CPi and S = sales price
In 1945, 40 = 18k or K = 20/9
Using this we can say
Sales price in 1999 would be k (166.6)
=
the price of good x in 1999 dollars is 370.89 dollars
Answer:

Step-by-step explanation:
we know that
In this problem we have a exponential function of the form

where
x ----> is the number of years since 2009
y ----> is the population of bears
a ----> is the initial value
b ---> is the base
step 1
Find the value of a
For x=0 (year 2009)
y=1,570 bears
substitute


so

step 2
Find the value of b
For x=1 (year 2010)
y=1,884 bears
substitute



The exponential function is equal to

step 3
How many bears will there be in 2018?
2018-2009=9 years
so
For x=9 years
substitute in the equation

