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4 years ago

5(- 3x - 2) - (x - 3) = -4(4x + 5) + 13 Solve

Mathematics

2 answers:

morpeh [17]4 years ago

8 0

Answer:

Always true or 0 = 0

Step-by-step explanation:

This equation simplifies to 0 = 0 I will show in several steps.

1. (-15x - 10) - (x - 3) = (-16x - 20) + 13

2. -16x - 7 = -16x - 20 + 13

3. 0 = 7 - 20 + 13

4. 0 = 0

Hope this helps! (Please consider giving brainliest)

grin007 [14]4 years ago

5 0

Answer:

all real value for x

Step-by-step explanation:

5(- 3x - 2) - (x - 3) = -4(4x + 5) + 13

Distribute

-15x -10 -x+3 = -16x -20 +13

Combine like terms

-16x-7 = -16x -7

Add 16x to each side

-16x-7 +16x= -16x -7+16x

-7 = -7

This is always true so x is all real values

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Can you Afford to Enlarge this?You each want to have a 3" X 5' picture ofprinted so that you canput it on your dartboard. It cos

Marizza181 [45]

Given:

$\text{ Dimension = 3}\times5$

Sol:

Area of picture is:

$\begin{gathered} =\text{ length}\times\text{ Width} \\ \\ =15 \end{gathered}$

If the cost $10 per square inch then price of 15 square inch is:

$\begin{gathered} =15\times10 \\ \\ =150 \end{gathered}$

If the quadruple of dimension that mean:

$\begin{gathered} \text{ l ength = 4 length} \\ \\ Width\text{ = 4 width} \end{gathered}$

So area is:

$\begin{gathered} A=4\text{ length}\times4\text{ Width} \\ \\ A=4(15) \\ \\ A=60 \end{gathered}$

So price is:

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3 0

1 year ago

What is the equation process to this question?

Andreyy89

The given equation is $h(t)=-16t^2+80t+4$ where h is the height, in feet, of a ball and t is the time, in seconds.

Part a: The height of the ball when t = 2 seconds:

The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(2)=-16(2)^2+80(2)+4$

Simplifying the terms, we get;

$h(2)=-64+160+4$

$h(2)=100$

Thus, the height of the ball after 2 seconds is 100 feet.

Part b: The height of the ball when t = 4 seconds:

The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(4)=-16(4)^2+80(4)+4$

Simplifying the terms, we get;

$h(4)=-256+320+4$

$h(4)=68$

Thus, the height of the ball after 4 seconds is 68 feet.

5 0

4 years ago

Please show your work, tysm :D ~giving brainliest!~

N76 [4]

Answer:

. 0625

Step-by-step explanation:

1/2^4

1/16

just doing half life

5 0

2 years ago

The expresion 14.42d + 12.24c can be used to find the total cost of d punds of almonds and c pounds of cashews how much does it

madam [21]

Answer:

Therefore the total cost of $3\frac{1}{2}$ pound of almonds and $3\frac{1}{2}$ pound of cashews is

$y=\frac{36.05}{d}+\frac{30.6}{c}$

[Where y is in $]

Step-by-step explanation:

[The unit of price is not given, I assume the unit of cost as $]

Given expression is 14.42 d + 12.24 c .

Where the amount of almond is denoted by d pounds.

and the amount of cashews is denoted by c pounds.

The cost price of d pound of almond is $14.42.

The cost price of 1 pound of almond is $\$\frac{14.42}{d}$

Then the cost of $3\frac{1}{2}$ pound of almond is $=\$\frac{ 14.42 \times3 \frac{1}{2} }{d}$

$=\$\frac{36.05}{d}$

Again from the given expression we get that,

The cost price of c pound of cashews is $12.24

The cost price of 1 pound of cashews is $=\$\frac{12.24}{c}$

Then the cost of $3\frac{1}{2}$ pound of cashews is $=\$\frac{ 12.24 \times3 \frac{1}{2} }{c}$

$=\$\frac{30.6}{c}$

Therefore the total cost of $3\frac{1}{2}$ pound of almonds and $3\frac{1}{2}$ pound of cashews is

y = $=\frac{36.05}{d}+\frac{30.6}{c}$

[Where y is in$]

7 0

3 years ago

Use the initial term and the recursive formula to find an explicit formula for the sequence an. Write your answer in simplest fo

agasfer [191]

From the recursive rule

$a_n = a_{n-1}-13$

it follows that

$a_{n-1}=a_{n-2}-13 \implies a_n = a_{n-2} - 2\times13$

$a_{n-2}=a_{n-3}-13 \implies a_n = a_{n-3} - 3\times13$

and so on. Notice how the subscript on a on the right side and the coefficient multiplied by 13 add up to n (n - 2 + 2 = n; n - 3 + 3 = n; and so on). If we continue the pattern, we'll end up with

$a_n = a_1 + (n-1)\times13$

so that the explicit rule for the n-th term in the sequence is

$a_n = -2 + 13(n-1) \implies a_n = \boxed{13n-15}$

6 0

3 years ago