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zmey [24]
3 years ago
14

Pls help me its for today 4x2 and three quarters

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
6 0

Answer

11

Step-by-step explanation:

Jlenok [28]3 years ago
5 0

Answer:

8

75 cents

Step-by-step explanation:

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zmey [24]

Answer:

-11

Step-by-step explanation:

first substitue the variables with the number then solve

-6(3)+7

-18+7= -11

4 0
3 years ago
Explain the error in the students work.
Usimov [2.4K]
They didn't distribute the 3 before doing the addition in the second step. They should've added 15 to both sides because 3*5 = 15
8 0
3 years ago
A hemispherical dome of a building needs to be painted. If the circumference of the base of the
soldier1979 [14.2K]

Answer:

The cost of painting the hemispherical dome is 110880 unit  

Step-by-step explanation:

Given as for a hemispherical dome :

The circumference of base = 17.6 m

The cost of painting it = 5 unit per 100 cm²

∵ circumference of base = circumference of circle = 2×\pi×radius

So ,17.6 m = 2×\pi×radius

Or, Radius = \frac{17.6\times 7}{2\times 22}

Or, Radius = \frac{123.2}{44} = 2.8 m

Or, R = 280 cm

So, Total surface area of hemispherical dome = 3×\pi×radius²

or, Total surface area of hemispherical dome = 3×\pi×280²

Or, Total surface area of hemispherical dome = \frac{3\times 22\times 280\times 280}{7}

Or, Total surface area of hemispherical dome = \frac{5174400}{7}

∴ Total surface area of hemispherical dome = 739200 cm²

Now, The cost of painting 100 cm² is 15 unit

So,   The cost of painting 739200 cm² = \frac{15\times 739200}{100}

Or, The cost of painting 739200 cm² = 110880 unit

Hence The cost of painting the hemispherical dome is 110880 unit  Answer

7 0
3 years ago
Solve the inequality <br><br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2x%7D%7Bx%20%2B%203%7D%20%20%5Cleqslant%203" id="Tex
Fofino [41]

Domain:x\neq-3\\\\\dfrac{2x}{x+3}\leq3\qquad\text{subtract 3 from both sides}\\\\\dfrac{2x}{x+3}-3\leq0\\\\\dfrac{2x}{x+3}-\dfrac{3(x+3)}{x+3}\leq0\\\\\dfrac{2x}{x+3}-\dfrac{3x+9}{x+3}\leq0\\\\\dfrac{2x-(3x+9)}{x+3}\leq0\\\\\dfrac{2x-3x-9}{x+3}\leq0\\\\\dfrac{-x-9}{x+3}\leq0\Rightarrow(x+3)(-x-9)\leq0\\\\x=-3,\ x=-9\\\\x\in(-\infty,\ -9]\ \cup\ (-3,\ \infty)

3 0
3 years ago
Out of 250 students 85 of them wear braces and 12 of them will be getting braces approximately what percent of students does not
uranmaximum [27]

approximately 2/3 of all students are not wearing braces because 165 (the difference of 250-85) /250 is 0.66

5 0
3 years ago
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