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Karolina [17]
1 year ago
9

Brandon enters bike races. He bikes 91 half miles every1 half hour. Complete the table to find how far Brandon bikes for each ti

me interval.
Help,

Mathematics
1 answer:
posledela1 year ago
4 0

Using proportions, it is found that he bikes:

  • 19 miles in one hour.
  • 28.5 miles in one and a hour.
  • 38 miles in two hours.
  • 47.5 miles in two and a hours.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

In this problem, the proportion is that he bikes 9.5 miles each half hour, hence:

  • In one hour, he bikes 2 x 9.5 = 19 miles.
  • In one and a half hour, he bikes 3 x 9.5 = 28.5 miles.
  • In two hours, 4 x 9.5 = 38 miles.
  • In two and a half hours, he bikes 5 x 9.5 = 47.5 miles.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

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37

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What is a necessary step for constructing perpendicular lines through a point off the line?
Nostrana [21]

Answer:

Find another point on the perpendicular line.

Step-by-step explanation:

Given an original line "m", and a point off the line "Q", in order to construct a second line "p", meant to be perpendicular to "m" through the point "Q", fundamentally, the only truly necessary step to construct a perpendicular line through is to find another point on the yet-to-be-found perpendicular line.

Most often, this is accomplished by exploiting the fact that "p" is the set of all points that are equidistant from any pair of points that are symmetric about "p".

Since the symmetry must be about "p", and we don't even know where "p" is, one often finds two points on "m" that are equidistant from "Q".

This can be accomplished by adjusting a compass to a fixed radius (larger than the distance from "Q" to "m"), and making an arc that intersects "m" in two places.  Those two places will be equidistant from "Q", and are simultaneously on line "m".  Thus, these two points, "A" & "B" are symmetric about "p".

Since "A" & "B" are symmetric about "p", they are equidistant from "p", and are on "m".  One could try to find the point of intersection between "p" and "m" through construction, but this is unnecessary.  We need only find a second point (besides "Q") that is equidistant from "A" & "B", which will necessarily be a point on "p", to form the line perpendicular to "m".

To do this, fix the compass with any radius, and from "A" make a large arc generally in the direction of "B", and make the same radius arc from "B" in the direction of "A" such that the two arcs intersect at some point that isn't "Q".  This point of intersection we can call point "T", and the line QT is line "p", the line perpendicular to the original line, necessarily containing "Q".

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2 years ago
A sprinkler sprays a section of 200 degrees with a radius of water reaching 5 meters.
beks73 [17]

Answer: The area that it covers is 78.53 square meters

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Area of a circle (A): π r²

Where:

r = radius (in our case is 5 meters)

So, replacing with the values given:

A= π (5)² = π 25 =78.53 square meters

In conclusion, the area that it covers is 78.53 square meters

Feel free to ask for more if needed or if you did not understand something.

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On a coordinate plane, the segment with endpoints (10, 40) and (70, 120) is
OlgaM077 [116]

Answer:

The length of the resulting segment is 500.

Step-by-step explanation:

Vectorially speaking, the dilation is defined by following operation:

P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)] (1)

Where:

O(x,y) - Center of dilation.

P(x,y) - Original point.

k - Scale factor.

P'(x,y) - Dilated point.

First, we proceed to determine the coordinates of the dilated segment:

(P(x,y) = (10, 40), Q(x,y) = (70, 120), O(x,y) = (0,0), k = 5)

P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]

P(x,y) = (0,0) +5\cdot [(10,40)-(0,0)]

P'(x,y) = (50,200)

Q'(x,y) = O(x,y) + k\cdot [Q(x,y)-O(x,y)]

Q' (x,y) = (0,0) +5\cdot [(70,120)-(0,0)]

Q'(x,y) = (350, 600)

Then, the length of the resulting segment is determined by following Pythagorean identity:

l_{P'Q'} = \sqrt{(350-50)^{2}+(600-200)^{2}}

l_{P'Q'} = 500

The length of the resulting segment is 500.

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