<span><span><span>
(2^2)</span>(x)</span>3</span>=<span>16
</span>Step 1: Multiply both sides by 3.
<span><span><span><span>(<span>2^2</span>)</span><span>(x)</span></span>3</span>=16
</span><span><span><span>(<span><span><span>(<span>2^2</span>)</span><span>(x)/</span></span>3</span>)</span>*<span>(3)</span></span>=<span><span>(16)</span>*<span>(3)</span></span></span><span><span><span>(<span>22</span>)</span><span>(x)</span></span>=48</span>
Step 2: Simplify both sides of the equation.
<span><span>4x</span>=48</span>
Step 3: Divide both sides by 4.
<span><span><span>4/x</span>4</span>=<span>48/4
</span></span><span>x=<span>12</span></span>
The question asked in this query is the place order of the
number value 20.4 and what is the tenths?
We can further explain the state order values of the number
is expanded form thus,
<span><span>1.
</span>20.0 – tens</span>
<span><span>
2.
</span>0.4 – tenths</span>
Now, which is the tenths in the number? It is the digit
number of 0.4
Y=7x+1
*note that the first number is always the x.
so,
a) (0,?)
y=7(0)+1
y=1
(0,1)
b) (3,?)
y=7(3)+1
y=21+1
y=22
(3,22)
